Answer please I need this ASAP

Find the differnce between 6 weeks 2 days and 3 weeks 5 days

konstantin123 [22]

Answer:

42

16

Step-by-step explanation: Well, 1 week = 7 days. So 6 weeks is 6x7 = 42. Because you are looking for the difference between them, you will subtract them. 42 - 2 = 40. And for the 2nd one. 3x7 =21. 21 - 5 = 16.

3 0

2 years ago

Read 2 more answers

Karma's brother was born

torisob [31]

Answer:

Basically just add 12 to the hour that you want

Step-by-step explanation:

I'm honestly not sure what you're asking...

but if it was 13 min after 8pm, then it would be 20:13

if it was 18 min after 8pm, then it would be 20:18

6 0

2 years ago

Sociology graduates, upon entering the workforce are normally distributed and earn a mean salary of $30,000 with a standard devi

GrogVix [38]

Answer:

0.62% probability that randomly chosen salary exceeds $40,000

Step-by-step explanation:

Problems of normally distributed distributions are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

$\mu = 30000, \sigma = 4000$

What is the probability that randomly chosen salary exceeds $40,000

This is 1 subtracted by the pvalue of Z when X = 40000. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{40000 - 30000}{4000}$

$Z = 2.5$

$Z = 2.5$ has a pvalue of 0.9938

1 - 0.9938 = 0.0062

0.62% probability that randomly chosen salary exceeds $40,000

7 0

2 years ago

The midsegment of a trapezoid is always parallel to each base true or false

Deffense [45]

Answer:

True

Step-by-step explanation:

we know that

The <u><em>Trapezoid Mid-segment Theorem</em></u> states that : A line connecting the midpoints of the two legs of a trapezoid is parallel to the bases, and its length is equal to half the sum of lengths of the bases

see the attached figure to better understand the problem

EF is the mid-segment of trapezoid

EF is parallel to AB and is parallel to CD

EF=(AB+CD)/2

so

The mid-segment of a trapezoid is always parallel to each base

therefore

The statement is true

8 0

2 years ago

Can someone PLEASE help me with Trigonometry???

Svetach [21]

$\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\
-------------------------------\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}
\\\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)
\\\\\\
\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}$

but anyway, the numerator will give the angles, and θ is just half of each

$\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\
-------------------------------\\\\
sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}
\\\\\\
sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o
\\\\\\
\theta=\cfrac{-8.05}{2}\implies \theta=-4.025$

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there

7 0

3 years ago