Use the distributive property on right side and solve:
3x-6=22-x
4x-6=22
4x=28
x=7
So the solution is x=7
Hope this helped!
Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
The number of red beads are increasing by 2 for each new pattern
The next number of reds will be 12. ( in patern 5)
number of blue beads in pattern 5 will be 15 ( increasing by 3 )
nth term for red = 4 + 2 (n-1) ( its an arithmetic sequence)
nth term for blue = 3 + 3(n - 1) - as above ,arithmetic.
Total beads in pattern 45 is
No. red beads in pattern 26 = 4 + 2(26-1) = 4 + 50 = 54
No blue beads in pattern 60 = 3 + 3(59) = 180
Total number of beads in pattern 45 is:-
4 + 2(44) + 3 + 3(44) = 227
Answer:
Distribute or Die part 2: Attack of the PEMDAS!
