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PSYCHO15rus [73]

4 years ago

7

What is x(x+2) expanded?

2 answers:

zubka84 [21]4 years ago

7 0

Answer: X²+2x

Step-by-step explanation:

Use FOIL method

First
Inner
Outer
Last

<u>Solve:</u>

x(x+2)

<h2>=x²+2x</h2>

SVETLANKA909090 [29]4 years ago

5 0

<em>☽------------❀-------------☾</em>

<em>Hi there!</em>

<em>~</em>

<em>What is </em> $x(x+2)$ <em> expanded?</em>

<em></em> $x(x+2)$ <em> in expanded form is :</em>

<em></em> $x^2 + 2x$ <em></em>

<em>Explanation :</em>

<em>Apply the distributive law: </em> $a( b + c ) = ab + ac$ <em></em>

<em></em> $x(x+2) = xx + x \times 2$ <em></em>

<em></em> $= xx + x \times 2$ <em></em>

<em>Then you simplify : </em> $xx + x \times 2 : x^2 + 2x$ <em></em>

<em></em> $= x^2 + 2x$ <em></em>

<em>❀Hope this helped you!❀</em>

<em>☽------------❀-------------☾</em>

<em></em>

<em></em>

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I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

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3 years ago

Jason is 22 years older than his sister joan. in 9 years, he will be twice as old as joan. how old is each of them now?

Liono4ka [1.6K]

Jason will be 36 and joan will be 27 years old.

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3 years ago

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svetlana [45]

A copy of a line segment will have the same measure or length as the segment.

The true statement is (4) They are congruent.

From the question, we understand that a copy of the line segment is created.

This means that the new segment has the exact property as the original line segment.

Hence, both lines are congruent, and the true statement is (d)

Read more about line segments at:

brainly.com/question/3573606

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3 years ago

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A region R in the xy-plane is given. Find equations for a transformation T that maps a rectangular region S in the uv-plane onto

ruslelena [56]

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