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Yakvenalex [24]

3 years ago

13

Please help(: ( 8th grade lesson)

1 answer:

trapecia [35]3 years ago

8 0

Step-by-step explanation:

Since angle 1 is on a straight line and we know that angle 4 is 160, and a straight line has a sum of 180 degrees, simply subtract 160 from 180 to get angle 1.

Angle one would be 180-160 = 20

Since the sum of angles in a triangle is 180 and we already know 2 of them, angle 1 is 20 and angle 3 is 30, just add them together and then subtract that from 180. 20 + 30 = 50, and 180 - 50 = 130.

So in conclusion:

Angle 1 is: 20

Angle 2 is: 130

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Operations with rational expressions

Scorpion4ik [409]

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}$

Solution:

Given expression:

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}$

To solve the given expression:

First simplify: $\frac{50-2 w^{2}}{3 w^{2}+9 w-30}$

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30}=-\frac{2(w+5)(w-5)}{3(w-2)(w+5)}$

Cancel the common factor (w + 5).

$$=-\frac{2(w-5)}{3(w-2)}$

Now substitute this in the given expression.

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{2(w-5)}{3(w-2)} \cdot \frac{w^{2}+5 w-14}{6 w-30}$

Multiply the fractions $\frac{a}{b} \cdot \frac{c}{d}=\frac{a \cdot c}{b \cdot d}$

$$=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{3(w-2)(6 w-30)}$

Factor the denominator $3(w-2)(6 w-30) =18(w-2)(w-5)$

$$=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{18(w-2)(w-5)}$

Cancel the common factor 2(w – 5).

$$=-\frac{w^{2}+5 w-14}{9(w-2)}$

Factor the numerator $w^{2}+5 w-14=(w-2)(w+7)$

$$=-\frac{(w-2)(w+7)}{9(w-2)}$

Cancel the common factor (w – 2).

$$=-\frac{w+7}{9}$

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}$

3 0

3 years ago

-3x + 7 = 1<br> what dose x represent

olchik [2.2K]

Answer:

the answer is x=3

Step-by-step explanation:

-3x=1-7

-3x=-6

-x=-6+3

-x=-3

x=3

3 0

3 years ago

Tom's grandmother gave him $10. Now Tom has $34. Which equation can be used to calculate how much money Tom had before his grand

azamat

Answer:

A.) a+10 = 34

Step-by-step explanation:

8 0

3 years ago

One-third times a number increased by eleven

MatroZZZ [7]

Answer:

1/3(n)+11

Step-by-step explanation:

n represents a number

7 0

3 years ago

On three examinations, you have grades of 85, 78, and 84. There is still a final examination, which counts as one grade In order

kirill [66]

Answer:

The average of the provided grades are 86.75

Step-by-step explanation:

Consider the provided information.

On three examinations, you have grades of 85, 78, and 84. In order to get an A your average must be at least 90.

In the last exam you get 100 marks now calculate the average by using the formula:

$\frac{\text{Sum of observations}}{\text{Number of observations}}$

$\frac{85+78+84+100}{5}$

$\frac{347}{5}$

$86.75$

86.75 is less than 90 so you will not get A.

The average of the provided grades are 86.75

6 0

4 years ago