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zhannawk [14.2K]
2 years ago
6

Find the GCF (pls help)

Mathematics
1 answer:
Pani-rosa [81]2 years ago
7 0

Answer:

i dont know the answer but if you search it up on the worksheet answer key may come up

Step-by-step explanation:

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Rashawn read 25 pages of his book each day until he finished the book. His book was 400 pages long.
tatyana61 [14]
B is your correct answer.

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3 years ago
12. For angle A it is known that sin(A)>0 and tan (A) <0. If A is drawn in standard position, in which quadrant
Dafna11 [192]

Answer:

Quadrant 2

Step-by-step explanation:

Sin = opp/hyp and opp is positive in quadrants 1 & 2.

Tan = opp/adj - we need one of these values to be positive and the other negative. adj is negative in quadrants 2 & 3.

Quadrant 2 is found in both of the scenarios that we need to occur.

8 0
3 years ago
Please help me and show your work
morpeh [17]

Answer:

Step-by-step explanation:

y = 3x + 4

Plugin x = 3 in the equation,

y = 3*3 + 4

 = 9 + 4

y = 13

Plugin x = 4 in equation,

y = 3*4 + 4

  = 12 + 4

y = 16

Plugin x = 5 in the equation,

y = 3*5 + 4

  = 15 + 4

y = 19

2) y =x - 7

Plugin x = 10 in the equation

y = 10 - 7

y = 3

Plugin x = 15 in the equation

y = 15 - 7

y = 8

Plugin x = 20 in the equation

y = 20 - 7

y = 13

6 0
2 years ago
Please HELP!!!!!
Stels [109]
Can you explain it more clear because my english is not very good, I want to easy to help you
3 0
2 years ago
If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
sweet-ann [11.9K]

Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

4 0
2 years ago
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