2 years ago

Find x intercepts of polynomial =a^2+16+64

Mathematics

1 answer:

Anuta_ua [19.1K]2 years ago

7 0

Answer:

Step-by-step explanation:

I think you mean a^2 + 16a + 64.

The x-intercepts are the values of a for which the polynomial equals zero.

a^2 + 16a + 64 = (a+8)^2 = 0

a = 8

The x-intercept is 8.

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