Answer:
The correct code to the given question is
if ((counter % 10) == 0) // check the condition
{
System.out.println("Counter is divisible by ten: " + counter); // display
}
else // check the condition
{
System.out.println("Counter is not divisible by ten: " +counter); // display the //value
}
counter++; // increment the value of counter
Explanation:
Following are the description of code
- In the given question we have to check the condition that the given number is divisible by 10 or not .
- In the if block if the number is divisible by 10 then it print the value of number and increment the value of counter .
- In the else block if the number is not divisible by 10 then it print the value of number and increment the value of counter .
- It means the value of counter is increases in the if block as well as in the else block .So we have to remove the counter statement from there and place outside the if and else block .
Answer:
Answer C
Explanation:
Static NAT creates a fixed translation of private addresses to public addresses. The main difference between dynamic NAT and static NAT is that static NAT allows a remote host to initiate a connection to a translated host if an access list exists that allows it, while dynamic NAT does not.
On Microsoft Word a
merge process involves the primary and secondary files. The correct choice is
the letter
C. Primary and secondary
<span>
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Answer:
The program in Python is as follows:
n = int(input("n:"))
total = 0
for k in range(1,n+1):
total+=k**3
print(total)
Explanation:
This gets input for n
n = int(input("n:"))
This initializes total to 0
total = 0
This iterates from 1 to n
for k in range(1,n+1):
This adds up the cube of each digit
total+=k**3
This prints the calculated total
print(total)
Answer:
The modified program is as follows:
user_input = input()
short_names = list(user_input.split(" "))
short_names.pop(0)
short_names[-1] = "Joe"
print(short_names)
Explanation:
This gets the user input
user_input = input()
This converts input to list
short_names = list(user_input.split(" "))
This removes the first item of the list
short_names.pop(0)
This updates the last item to "Joe"
short_names[-1] = "Joe"
This prints the updated list
print(short_names)