Let x be ml of 5% soln.
let 500-x be ml of 25% soln.
.
x*.05=.05x
(500-x)*.25=125-.25x
500*.20=100
.
.05x+125-.25x=100
-.2x=-25
x=-25/-.2
x=125 ml of 5% soln.
500-x=375 ml of 25% soln.
.
Check:
125*.05= 6.25
375*.25=93.75
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========100
Answer:
-2/9
Step-by-step explanation:
Answer:6km
Step-by-step explanation:
Given
when Alice finishes the race Becky is 8km From finishing line
and caitlin 12 km from finishing line.
Suppose t is the time require by Alice to finish the race
and
be the velocity of alice ,becky and caitlin
thus 
thus 
say t' is time required by beckey to complete 8 km thus

therefore for Caitlin

Thus caitlin will cover a distance of 6 km in t' time and 6 km away from finishing.
Equation D does not give the correct value of w because P= 2W + 2L. If needed I can explain more in depth.