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2 years ago

What must the measure of the

Mathematics

1 answer:

WITCHER [35]2 years ago

6 0

Answer:

Linear pair angle of 136 degree =180-136

=44

Therefore angle y is alternate angle of 44

Therefore angle y=44

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2.98 times 10 to the 3rd power in standard notation

stiks02 [169]

Answer:

2980

Step-by-step explanation:

2.98*10^3 = 2980

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3 years ago

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Which of these is equal to cos 47°?

tigry1 [53]

C tan 43 I think it right

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3 years ago

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An angle that measures 82° is bisected. What is the measure of each resulting angle?

Leni [432]

When an angle is bisected, it is cut exactly in half.

82/2 = 41.

The resulting two angles will each be 41 degrees.

Your answer is C.

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2 years ago

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For which function is the ordered pair (5,10) not a solution ?

PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

Because

a) 10 = 2(5) = 10

b) 10 = 5 + 5 = 10

c) 10 = 15 -5 = 10

d) 10 = 5 - 5 = 0 the result is not equivalent

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2 years ago

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Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).

Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5$

well then therefore

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}$

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}$

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2 years ago