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3 years ago

Can anyone help me with this question please.

Mathematics

2 answers:

sveticcg [70]3 years ago

6 0

No se Nota nada tomalo bien la foto

Anika [276]3 years ago

3 0

Answer:

it will be the last box to make a right triangle

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Mario has nine Green, eight red, 10 brown, six orange, and nine blue M&Ms what fraction of the M&Ms are orange

gizmo_the_mogwai [7]

6 orange. 42 total. 6/42 = 1/7 of the M&Ms are orange.

6 0

2 years ago

The next model of a sports car will cost 5.2% less than the current model. The current model costs $41,000. How much will the pr

Ivanshal [37]

The price will decrease by $2132

<u>Step-by-step explanation</u>

Given that the next model of the sports car will cost 5.2% less than the current model.

The price of the current model=$41000

The price of the next model will be 5.2% less than $41000

$price\ of\ next\ model=price\ of \ current \ model \times(100-5.2)/100\\=41000\times 94.8/100\\=38868$

$decrease in price=41000-38868=2132$

There is a $2132 decrease in prize of the sports car.

3 0

3 years ago

Solve for the values of x and y.

Tasya [4]

Answer:

We can’t solve for x and y

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

2 years ago

What does d equal in -24 + 12 (d - 3) + 22

zubka84 [21]

Answer:

-24+12(d-3)+22=-24+34(d-3)

10(d-3)

10d=-30

d=-30/10

d=3

4 0

3 years ago