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Goshia [24]
3 years ago
7

Can anyone help me with this question please.

Mathematics
2 answers:
sveticcg [70]3 years ago
6 0

No se Nota nada tomalo bien la foto

Anika [276]3 years ago
3 0

Answer:

it will be the last box to make a right triangle

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When simplified and written in standard form, which quadratic function is equivalent to the polynomial shown?
mars1129 [50]

Answer:

2c^2 - 2c - 3

Step-by-step explanation:

Next time, please share the answer choices.  Thank you.

Group together the 'c' terms in 2 + 7c – 4c2 – 3c + 4:

                                                     2  + 4c and -4c^2 + 4  Then we have:

-4c^2 + 4c + 6

We should reduce this by factoring -2 out of all three terms:

2c^2 - 2c - 3  This is the desired quadratic in standard form.

3 0
2 years ago
A unit rate is a ratio that compares an amount of one quantity to _______________ unit of another quantity.
masya89 [10]

Answer:

one

Step-by-step explanation:

A unit rate compares a quantity to one unit of measure.

6 0
2 years ago
Can I get a help please ​
iogann1982 [59]

Answer:

middle graph

Step-by-step explanation:

Soluton

The  second (middle ) graph is the only one that works.

  • First of all when you simplicity the right, you get y = x^2 - 1). That means that x does not go through 0,0. If you put x = 0 into x^ -  1 = 0, you get - 1. So on that basis alone both the first and third graphs are incorrect.
  • Second, both xs in the factors are plus, so x^2 is plus, which means the graph opens upward.

6 0
2 years ago
Of the 20 students in Emily's class 15 like chocolate cake and the rest like cheesecake how many like cheesecake and what percen
alisha [4.7K]
5 students like cheesecake because if there is 20 students in all and 15 like chocolate and the rest like cheesecake you do 20-15=5

If 5 students like cheesecake out of 20 it would be 5/20 20*5=100 just multiply by 5 5*5=25%


25% of students like cheesecake 
4 0
3 years ago
Read 2 more answers
Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

3 0
3 years ago
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