X + y = 5 y = 3x + 1 How do I find the solution from these two equations by graphing

Mathematics

2 answers:

Mnenie [13.5K]3 years ago

7 0

Hope it helps

Have a good day

Mandarinka [93]3 years ago

5 0

Answer:

x=1, y=4

Step-by-step explanation:

x+y=5 - (1)

y=3x + 1 (2)

Sub (2) into (1)

x + (3x +1)=5

4x=5-1

x=4 ÷4

Sub x=1 into (2)

y=3(1)+1

= 4

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Identify the x-intercepts of the function below f(x)=x^2+12x+24

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x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

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Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

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Now, let us find the zeroes using quadratic formula for f(x) = 0.

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Here, for (1) a = 1, b= 12 and c = 24

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$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$