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3 years ago

Eileen spent 75 cents of her dollar at the market. how much money does she have left ???

Mathematics

1 answer:

givi [52]3 years ago

5 0

Answer:

25 cents

Step-by-step explanation:

In perspective, that's 0.25 of her dollar left

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What is the volume of the cylinder shown below?

sveta [45]

Answer:

1008pi

Step-by-step explanation:

the formula for volume of a cylinder is pi r squared h

V equals 144 * 7 * pi

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3 years ago

Given that f(x)=2x+3 and g(x)=x-6, what is the composition f(g(1))?

Tresset [83]

Answer:

D/0

Step-by-step explanation:

the domain of (g o f )(x) is "all x > 0".

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3 years ago

Williiam lost 25% of his marble,gave 1/6 of the remainder to his.Brother and had 120 marbles left.How many marbles did he have a

bija089 [108]

Answer:

Number of marbles with Williams at the starting = 192

Step-by-step explanation:

Let total number of marbles with Williams = m

He lost marbles = 25% of the total number

= $\frac{25}{100}\times m$

= $\frac{m}{4}$

Remaining marbles with Williams = m - $\frac{m}{4}$

= $\frac{3m}{4}$

He gave marbles to his brother = $\frac{1}{6}$ th of the remaining marbles

= $\frac{1}{6}\times \frac{3m}{4}$

= $\frac{m}{8}$

Remaining marbles after giving marbles to his brother = 120

Therefore, $\frac{3m}{4}-\frac{m}{8}=120$

$\frac{6m}{8}-\frac{m}{8}=120$

$\frac{5m}{8}=120$

m = $\frac{120\times 8}{5}$

m = 192

Number of marbles with Williams at the starting = 192

5 0

3 years ago

What is five times less than the toyal cost of 69 dollars.

bezimeni [28]

It should be 13.8. hope this helps

4 0

3 years ago

In 1967, New Zealander Burt Munro set the world record for an Indian motorcycle, on the Bonneville Salt Flats in Utah, with a ma

bagirrra123 [75]

Answer:49 sec

Step-by-step explanation:

Given

Maximum speed to reach is 183.58 mi/h

Length of course is 5 mi

acceleration rate is defined by 60mi/h in 4 sec

therefore acceleration(a) $=\frac{v-u}{t}$

$a=\frac{60\times 60\times 60}{4}$

$a=54\times 10^3 mi/h^2$

To reach a speed of 183.58mi/h with an acceleration of $54\times 10^3 mi/h^2$

Using equation of motion

v=u+at

$183.58=0+(54\times 10^3)t$

$t=\frac{183.58}{54\times 10^3}$

t=0.00339 hours

t=12.23 s reach maximum speed

To complete course it takes

$s=ut+\frac{1}{2}at^2$

$5=0+\frac{1}{2}\times 54\times 10^3 \times t^2$

t=0.01360 hour

or $t=48.98\approx 49 s$

7 0

3 years ago