If you mean the m^3=105, then m^6 will be
![( \sqrt[3]{105}) ^6](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B3%5D%7B105%7D%29%20%5E6)
which is 105^2 which is
11025
Answer:
Lol don’t know
Step-by-step explanation:
Have a nice day uvu
Answer:
- -6x² - 6 = -7x - 9
- -6x² + 7x - 6 + 9 = 0
- -6x² + 7x + 3 = 0
- 6x² - 7x - 3 = 0
<u>Discriminant:</u>
- D = (-7)² - 4*6*(-3) = 49 + 72 = 121
<u>Since D > 0, there are 2 real solutions:</u>
- x = (- (-7) ±√121 )/12
- x = (7 ± 11)/12
- x = 1.5, x = -1/3
Answer:
Trent has 6 quarters and 5 dimes.
Step-by-step explanation:
Consider the provided information.
Let q = Number of quarters
d = Number of dimes.
Trent has 11 quarters and dimes.


The worth of a quarter is 25 cents.
The worth of a dimes is 10 cents

Substitute the value of q in above equation.


Substitute the value of d in 


Hence, Trent has 6 quarters and 5 dimes.
<span><span>tan^2</span>(x) is the answer.</span>