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Aneli [31]
3 years ago
15

Given that a:b = 5:4 and b/c = 7:3 find: a:b:c

Mathematics
1 answer:
USPshnik [31]3 years ago
8 0

a/b=5/4

a=5k

b=4k

b/c=7/3

b=7x

c=3x

b=4k

b=7x

4k=7x   =>

k=7y

x=4y

a/b/c=

=5*7*y/4*7*y/3*4*y=

=35y/28y/12y=

=35/28/12y=

=5/4/12y=

=1,25/12y=

=0.1041666666666667/ y

there may be a mistake in my answer

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