What is being solved for is r.
Sketch a right
triangle having adjacent side(A) is given as “3”, hypotenuse side (H) is “x”
and assigning angle “a” as the angle between A and H. Using Pythagorean theorem,
you will get “square root of x-squared minus 9” as the opposite side (O). Using
SOH CAH TOA function, and since secant is the reciprocal of cosine, sec(a) =
x/3. Thus, a = arcsec(x/3). The remaining expression tan(a) is Opposite side
over Adjacent side which is equal to “square root of x^2 - 9” over "3". Therefore, the
algebraic expression would be: tan(arcsec(x/3)) = “sqrt (x^2 -9)” /3. Different answers can be made depending on which side you consider the “3” and “x”.
Answer:
, the third one
Step-by-step explanation:
Explaining the sine function:
The sine function is defined by:
In which A is the amplitude, 
is the period, 
is the horizontal shift and V is the vertical shift.
So, in your problem:
The amplitude is 4, so A = 4.
The period is 
, so 
.
There is no horizontal shift, so 
.
The vertical shift is −3, so V = -3.
The sine function that represents these following conditions is
, the third one
Answer:
7m + 5
Step-by-step explanation:
1) Simplify.
(12m + 1) - 1 (5m - 4) -> (12m + 1) - 5m + 4
2) Eliminate unnecessary parenthesis.
(12m + 1) - 5m + 4 -> 12m + 1 - 5m + 4.
3) Combine like terms.
12m - 5m = 7m, 4 + 1 =5 -> 7m + 5
The solution is 7m + 5
Answer:
<h2>x-intercept = 125 → (125, 0)</h2><h2>y-intercept = 275 → (0, 275)</h2>
Step-by-step explanation:
The x-intercepts are where the graph crosses the x-axis, and the y-intercepts are where the graph crosses the y-axis.
Look at the picture.
