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3 years ago

Find the area of the right triangle.

Mathematics

2 answers:

disa [49]3 years ago

8 0

54 is th answer because ther is 6 units on one side and 9 units in the other and when you times you get this I think

solniwko [45]3 years ago

4 0

Answer:

$\frac{1}{2} \times 9 \times 6 = 27 \\$

You have to count the units then put the rule

$\frac{1}{2} \times base \: \times hight$

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How do you check your answer for volume of a cylinder? Desperate need of answering

murzikaleks [220]

1. Make sure you're using the correct formula for the dimensions given. The usual formula gives volume in terms of radius and height. If you are given the diameter, the formula will be different, or you need to compute the radius before you use the formula.

2. Make sure you're using the appropriate value for π. Many calculators have the value built-in. Many problems posted on Brainly require the use of 3.14, which will give different answers. (One recent problem required the use of 3.) If your calculator doesn't have π built in, a reasonable value is 355/113, which is good to 7 significant figures.

3. Make sure the units you are using are compatible (generally, all the same). If your height is in one unit (say inches) and your diameter is in another unit (say centimeters), you need to do units conversion before you put the numbers in the formula. The result of putting your units in the formula with your numbers should be that you end up with units cubed. For example, for a radius of 2 cm and a height of 3 cm, the volume will be
.. V = π(2cm)^2*(3 cm) = 12π cm^3.

4. Compare the dimensions and the volume to things you know. You know the approximate size of a gallon jug, a 2 liter pop bottle, a 5-gallon bucket. Check your answer for reasonableness.

5. Make an estimate based on the dimensions. Round to 1 or 2 significant figures and make a guess as to the approximate result you should get. For this, you can use 3 for π, as you just want to be "somewhere in the ballpark" as opposed to being off by a factor of 10 or more. This requires a certain amount of number sense and knowledge of multiplication tables.

6. Make certain your calculator is being used correctly. If parentheses are involved, make sure you enter the closing parentheses--as opposed to letting the calculator put them in according to its own rules. If division or fractions are involved, make sure you have parentheses around the denominator in every case. 1/2*3 ≠ 1/(2*3) It can be helpful to use a calculator that shows you what it did. (The Google calculator does that, for example.)

7. Sometimes, it helps just to do the calculation twice (possibly in a different order). Inadvertent error can creep in even when you think you're paying attention.

8. If you're doing the math by hand, make use of all available techniques for checking your arithmetic.

7 0

3 years ago

A hummingbird weighed w ounces. One day the hummingbird drank 8 times its weight in water and ate half its weight in food. Which

Alexxandr [17]

T=8w+w/2
i hope this helps :)

5 0

2 years ago

PLEASE HELP

hram777 [196]

Answer:

answer; a)5√11/11

3 0

3 years ago

Suppose you are working in an insurance company as a statistician. Your manager asked you to check police records of car acciden

pochemuha

Answer:

(a) 95% confidence interval for the percentage of all car accidents that involve teenage drivers is [0.177 , 0.243].

(b) We are 95% confident that the percentage of all car accidents that involve teenage drivers will lie between 17.7% and 24.3%.

(c) We conclude that the the percentage of teenagers has not changed since you join the company.

(d) We conclude that the the percentage of teenagers has changed since you join the company.

Step-by-step explanation:

We are given that your manager asked you to check police records of car accidents and out of 576 accidents you selected randomly, teenagers were at the wheel in 120 of them.

(a) Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ ~ N(0,1)

where, $\hat p$ = sample proportion teenage drivers = $\frac{120}{576}$ = 0.21

n = sample of accidents = 576

p = population percentage of all car accidents

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population population, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ ]

= [ $0.21-1.96 \times {\sqrt{\frac{0.21(1-0.21)}{576} }}$ , $0.21+1.96 \times {\sqrt{\frac{0.21(1-0.21)}{576} }}$ ]

= [0.177 , 0.243]

Therefore, 95% confidence interval for the percentage of all car accidents that involve teenage drivers is [0.177 , 0.243].

(b) We are 95% confident that the percentage of all car accidents that involve teenage drivers will lie between 17.7% and 24.3%.

(c) We are also provided that before you were hired in the company, the percentage of teenagers who where involved in car accidents was 18%.

The manager wants to see if the percentage of teenagers has changed since you join the company.

Let p = percentage of teenagers who where involved in car accidents

So, Null Hypothesis, $H_0$ : p = 18% {means that the percentage of teenagers has not changed since you join the company}

Alternate Hypothesis, $H_A$ : p $\neq$ 18% {means that the percentage of teenagers has changed since you join the company}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} }}$ ~ N(0,1)

where, $\hat p$ = sample proportion teenage drivers = $\frac{120}{576}$ = 0.21

n = sample of accidents = 576

So, test statistics = $\frac{0.21-0.18}{\sqrt{\frac{0.21(1-0.21)}{576} }}$

= 1.768

The value of the sample test statistics is 1.768.

Now at 0.05 significance level, the z table gives critical value of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the the percentage of teenagers has not changed since you join the company.

(d) Now at 0.1 significance level, the z table gives critical value of -1.6449 and 1.6449 for two-tailed test. Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the the percentage of teenagers has changed since you join the company.

4 0

3 years ago

Solve the equation. 2/3b - 1/3b +12= 16

Elena-2011 [213]

Answer:

b=1/12 or just 12

Step-by-step explanation:

combine like terms

1/3b +12=16

subtract 12 on both sides

1/3b=4

divided both sides with 1/3

b= 12 or 1/12

hope this helps.. :/

8 0

3 years ago