First let that number be y.
List the equation by the given info.
y x 112/100 = 56
Shift y to the other side by turning it to ÷y.
112/100 = 56/y
Use cross method,
100 x 56 = 112y
5600 = 112y
y = 50
Therefore that number is 50
Answer:
The answer is,
Step-by-step explanation:
Firstly, you have to get rid of fraction by multiplying (r-3) to both side and expand out:
t × (r-3) = r/(r-3) × (r-3)
rt - 3t = r
Then you have to move all the "r" variables to one side and other variables to the other side:
rt - r = 3t
You can make "r" as a subject by taking out the common term, you can see that the common term on the left is "r" so you can bring out:
r(t-1) = 3t
r = 3t/(t-1)
Answer:
W=88
Step-by-step explanation:
4*(c-66)=c
4c-66*4=c
3c=66*4
c=22*4
c=88
w=88
Answer:
r - 5 = 2c
r = 75
Step-by-step explanation:
To write an equation for the problem, we first need do declare the value of the number of apps cora has.
Let c = Cora's apps
r - 5 = 2c
r - 5 is used to indicate that Rita deleted 5 apps.
2c is used to represent the twice the number of apps Cora has.
Now you said that Cora had 35 apps.
Let's plug that into the equation.
r - 5 = 2c
r - 5 = 2(35)
r - 5 = 70
Now we transpose the -5 to the other side to leave r.
r = 70 + 5
r = 75
So if Cora has 35 apps, then Rita will have 75 apps.