Answer:
The degrees of freedom is 11.
The proportion in a t-distribution less than -1.4 is 0.095.
Step-by-step explanation:
The complete question is:
Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4 if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion
Solution:
The information provided is:
Compute the degrees of freedom as follows:
Thus, the degrees of freedom is 11.
Compute the proportion in a t-distribution less than -1.4 as follows:
*Use a <em>t</em>-table.
Thus, the proportion in a t-distribution less than -1.4 is 0.095.
Answer:
the awnser to L is 25° or c
Answer:
3 + X
Step-by-step explanation:
Is your aljebra expression.
Answer:
1
Step-by-step explanation:
y=mx+b, equation for slope-intercept line
we can work out the equation based on given two points (1,1) and (7,4)
- m=(y2-y1)/(x2-x1)= (4-1)/(7-1)= 3/6= 1/2
y=1/2x+b
For (1,1)
For (7,4)
So we get
The answer is 1 for question mark
P = 300 + 60t
540 = 300 + 60t
540-300 = 60t
240 = 60t
240/60 = 4 (4 years after 2010)
So the year should be 2014