Write the following series in sigma notation. 8+18+28+38
1 answer:
Answer:
Step-by-step explanation:
Given the series 8 + 18 + 28 + 38
First, we need to find the sum of the nth term of the sequence as shown
Sn = n/2[2a+(n-1)d]
n is the number of terms
a is the first term = 8
d is the common difference = 18-8 = 28-18 = 10
Substitute
Sn = n/2 [2(8)+(n-1)*10]
Sn = n/2 [16+10n-10]
Sn = n/2[10n+6]
Sn = 2n/2(5n+3)
Sn = n(5n+3)
Sn = 5n²+3n
In Sigma form;
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Answer:
50 units
Step-by-step explanation:
you use Pythagorean-theorem which means A^2+B^2 =C^2
It does not matter the order of A and B because it is adding. But C is the hypotenuse.
If we plug in the # this is what it looks like...
14^2 +48^2=C^2
or
48^2+14^2=C^2
14*14= 196
48*48=2,304
then you add
196+2,304=C^2
2,500= C^2
and you can use a calculator for this part you do 2,500
with the 2,500 you use the sign as in the picture and it gives you...
50
which means 50*50 = 2,500
Answer:
Step-by-step explanation:
value after five years = $18,000×(1-0.12)⁵ = 18,000×0.88⁵ = $9,499.17
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The value drops below $2,000 in the 17th year.
