Answer:
if 2 means multiply by 2, the answer would be 12. If it just is there as a hint then the answer is 24.
Step-by-step explanation:
Hope this helps!
Answer:
52488y²
Step-by-step explanation:
first solve for 3³. then solve for 18²
3³=27
18²=324
27*324=8748
then multiply 8748 by 6y²
=52488y^2
1. It's all about pattern matching, as a lot of math is.
Letter A corresponds to letter J, as both are first in the names of their respective triangles.
Letter B corresponds to letter K, as both are second in the triangle names. Likewise, letter C corresponds to letter L, as both are last.
Realizing this, it should not be too much of a stretch to see
∠B ⇒ ∠K ∠C ⇒ ∠L AC ⇒ JL BC ⇒ KL2. Same deal. Match the patterns. Here, you're counting rings in the angle marks.
1 ⇒ 1, so A ⇒ R
2 ⇒ 2, so B ⇒ Q
since the figures are reportedly similar, you can continue in the same order to finish.
ABCD ~ RQPS3. The marked triangles cannot be similar. There are a number of ways to figure this. Basically, you want the ratios of sides to be the same for any similar triangles.
Here, you can eliminate the marked ones because the short side is too short relative to the others. (The average of the other two sides is double the short side in the similar triangles.)
Answer:
Step-by-step explanation:
Angle PRS and RPQ are right angles. Segment SP is also congruent to segment QR. This means that triangle PRS and RPQ are right angle triangles.
Segment SP and segment QR are the longest sides and thus, the hypotenuse of each triangle. It means that the hypotenuse are congruent
The hypotenuse leg theorem states that any two right triangles are congruent if they have a congruent hypotenuse and a corresponding congruent leg. Therefore,
Angle PSR is congruent to angle RPQ and
Triangle PSR is congruent to triangle RPQ
<h3>
Question: </h3><h3>
In the diagram below of Δ ABC, side BC is extended to point D, m∠A = x , m∠B = 2x+15, and m∠ACD = 5x+5 , what is m∠B ?</h3>
Answer: 3) m∠B = 25º
Step-by-step explanation:
Since m∠C is supplementary to m∠ACD
m∠C = 180º - m∠ACD
m∠C = 180º -(5·x + 5)
m∠C = 180º -5 -5·x
m∠C = 175º - 5·x
The sum of the angles of a triangle = 180º
m∠A + m∠B + m∠C = 180º
x + 2·x + 15º + 175º - 5·x = 180º
3·x - 5·x +190º = 180º
-2·x = 180º - 190º
-2·x = -10º
x = -10º/-2 = 5º
Now we can substitute this value of x in m∠B
m∠B = 2x+15
m∠B = 2·x + 15º = 2·5º + 15º = 10º + 15º = 25º
Answer: 3) m∠B = 25º
<h2><em>Spymore</em></h2>