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Andrew [12]
3 years ago
12

Hernando and Rachel are factoring 2mp-6p+27-9m. Is either of them correct? Explain your reasoning,

Mathematics
1 answer:
vichka [17]3 years ago
3 0

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as Hernando and Rachel's solution are not provided. So, I will just solve the question directly.

Given

2mp-6p+27-9m

Required

Factor

2mp-6p+27-9m

Group into 2

2mp-6p+27-9m = [2mp-6p]+[27-9m]

Factor each group

2mp-6p+27-9m = 2p[m-3]+9[3-m]

Rewrite 3 - m as -(m-3)

So, we have:

2mp-6p+27-9m = 2p[m-3]-9[m-3]

Factor out m - 3

2mp-6p+27-9m = [2p-9][m-3]

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