Question

Hernando and Rachel are factoring 2mp-6p+27-9m. Is either of them correct? Explain your reasoning,

Answer 1

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as Hernando and Rachel's solution are not provided. So, I will just solve the question directly.

Given

$2mp-6p+27-9m$

Required

Factor

$2mp-6p+27-9m$

Group into 2

$2mp-6p+27-9m = [2mp-6p]+[27-9m]$

Factor each group

$2mp-6p+27-9m = 2p[m-3]+9[3-m]$

Rewrite 3 - m as -(m-3)

So, we have:

$2mp-6p+27-9m = 2p[m-3]-9[m-3]$

Factor out m - 3

$2mp-6p+27-9m = [2p-9][m-3]$