Answer: Our required probability is 0.947.
Step-by-step explanation:
Since we have given that
Number of light bulbs selected = 30
Probability that the light bulb produced in a facility are defective = 2.8% = 0.028
We need to find the probability that fewer than 3 defective bulbs are found.
We will use "Binomial distribution":
n = 30, p = 0.028
so, P(X>3)=P(X=0)+P(X=1)+P(X=2)
So, it becomes,
and
So, the probability that fewer than three defective bulbs are defective is given by
1 over the 3 + 7 x 5 5.6
multiplyn 1.3
divide 5.6
subtract 0.3
answer is 1/5
Answer: 20
Step-by-step explanation:
17 is closest to 20 :)
(sorry if this is wrong)
Answer:
Step-by-step explanation:
We can subtract the first equation from the second to find the value of 
, although we can also do this vice versa.
Now, we can use substitution to solve for 
:
(pick any equation for substitution)
Hope this helps :)
Answer: $1.75
Step-by-step explanation:
Increase 1.25 by 4.25
5.31
Presently increase 1.25 by 2.85
3.56
Take away 3.56 from 5.31
1.75
