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Artemon [7]
3 years ago
5

Help me I beg you ......

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
3 0
Question i need more info
do you
i would like to
help you but
you don’t understand
with the cinnamon
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Scores on an English test are normally distributed with a mean of 31.5 and a standard deviation of 7.3. Find the score that sepa
vladimir1956 [14]

If X is a random variable representing test scores, then the 41st percentile is the score x such that P(X\le x)=0.41. Transform X to the random variable Z that follows the standard normal distribution via X=31.5+7.3Z:

P(X\le x)=P\left(\dfrac{X-31.5}{7.3}\le\dfrac{x-31.5}{7.3}\right)=P\left(Z\le\dfrac{x-31.5}{7.3}\right)=0.41

The z-score for the 41st percentile is about -0.2275, so

\dfrac{x-31.5}{7.3}\approx-0.2275\implies\boxed{x\approx29.8}

6 0
4 years ago
GUYS I NEED AN EXPLANATION RIGHT NOW!!!!!!!!!!!!<br> I'm scared, look at his explanation
natta225 [31]

Answer:

what ???

Step-by-step explanation:

6 0
3 years ago
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Which is the graph of y = cos(x) + 3?
Elena-2011 [213]
Hi, I hope this helps !

5 0
3 years ago
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Order the intergers from least to graestest 6 16 -8 -5
marissa [1.9K]

Answer:

-8, -5, 6, 16

Step-by-step explanation:

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8 0
3 years ago
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Please explain how you came to your answer, need help ASAP. Will give brainliest
shusha [124]
The vertex is the high point of the curve, (2, 1). The vertex form of the equation for a parabola is
.. y = a*(x -h)^2 +k . . . . . . . for vertex = (h, k)

Using the vertex coordinates we read from the graph, the equation is
.. y = a*(x -2)^2 +1

We need to find the value of "a". We can do that by using any (x, y) value that we know (other than the vertex), for example (1, 0).
.. 0 = a*(1 -2)^2 +1
.. 0 = a*1 +1
.. -1 = a

Now we know the equation is
.. y = -(x -2)^2 +1

_____
If we like, we can expand it to
.. y = -(x^2 -4x +4) +1
.. y = -x^2 +4x -3

=========
An alternative approach would be to make use of the zeros. You can read the x-intercepts from the graph as x=1 and x=3. Then you can write the equation as
.. y = a*(x -1)*(x -3)
Once again, you need to find the value of "a" using some other point on the graph. The vertex (x, y) = (2, 1) is one such point. Subsituting those values, we get
.. 1 = a*(2 -1)*(2 -3) = a*1*-1 = -a
.. -1 = a
Then the equation of the graph can be written as
.. y = -(x -1)(x -3)
In expanded form, this is
.. y = -(x^2 -4x +3)
.. y = -x^2 +4x -3 . . . . . . same as above
5 0
4 years ago
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