Question

HELP!! Not hard, just confusing.. ΔABC is reflected across the x-axis and then translated 4 units up to create ΔA′B′C′. What are the coordinates of the vertices of ΔA′B′C′ ?
A′(-3, 3), B′(-1, 1), C′(-2, 3)

A′(3, -3), B′(1, -1), C′(2, -3)

A′(3, -5), B′(1, -7), C′(3, -5)

A′(-3, 3), B′(-1, 1), C′(-2, -3)

Answer 1

Correct answer is A.

The reflection across the x-axis changes the sign of the y-coordinate of the point, while the x-coordinate remains the same.

A(-3, 1) $\rightarrow$ A''(-3, -1)
B(-1, 3) $\rightarrow$ B''(-1, -3)
C(-2, 1) $\rightarrow$ C''(-2, -1)

Translation 4 units up increases the y-coordinate for 4, while the x-coordinate remains the same.

A''(-3, -1) $\rightarrow$ A'(-3, 3)
B''(-1, -3) $\rightarrow$ B'(-1, 1)
C''(-2, -1) $\rightarrow$ C'(-2, 3)