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Alexeev081 [22]
3 years ago
6

IF U ANWSER I REPORT >:D

SAT
2 answers:
Rudiy273 years ago
7 0

Answer:

idc

Explanation:

Virty [35]3 years ago
5 0
Okie. Go ahead. Try meh. You have a nice day, scrub.
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Which is a property to every mixture
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Struggling with the following SAT Practice math question:
Kitty [74]

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3 0
3 years ago
What are all possible values of
kompoz [17]
Odd. Hence +1
r
+
1
is even, and one of
p
and
q
must be 2
2
. We may assume that =2
p
=
2
. Then we get 2=+1
2
q
=
r
+
1
and
8+22=2+1=(+1)(−1)+2=2(2−2)+2,
8
+
2
q
2
=
r
2
+
1
=
(
r
+
1
)
(
r
−
1
)
+
2
=
2
q
(
2
q
−
2
)
+
2
,
implying 22−4−6=0
2
q
2
−
4
q
−
6
=
0
or (−3)(+1)=0
(
q
−
3
)
(
q
+
1
)
=
0
. This has =3
q
=
3
as only prime solution, hence =3
q
=
3
and =2−1=5
r
=
2
q
−
1
=
5
.

In conclusion, there are two solutions: (,,)=(2,3,5)
(
p
,
q
,
r
)
=
(
2
,
3
,
5
)
and (,,)=(3,2,5)
(
p
,
q
,
r
)
=
(
3
,
2
,
5
)
.
6 0
3 years ago
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