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GREYUIT [131]
3 years ago
15

Equations with variables on both sides: decimals & fractions, 6d - 11/2 = 2d - 13/2

Mathematics
2 answers:
Paraphin [41]3 years ago
7 0

Final Answer: d = -\frac{1}{4}

Steps/Reasons/Explanation:

Question: Equations with variables on both sides: decimals & fractions, 6d - \frac{11}{2}  = 2d - \frac{13}{2}.

<u>Step 1</u>: Subtract 2d from both sides.

6d - \frac{11}{2} - 2d = -\frac{13}{2}

<u>Step 2</u>: Simplify 6d - \frac{11}{2} - 2d to 4d - \frac{11}{2}.

4d - \frac{11}{2} = -\frac{13}{2}

<u>Step 3</u>: Add \frac{11}{2} to both sides.

4d = -\frac{13}{2} + \frac{11}{2}

<u>Step 4</u>: Simplify -\frac{13}{2} + \frac{11}{2} to -1.

4d = -1

<u>Step 5</u>: Divide both sides by 4.

d = -\frac{1}{4}

~I hope I helped you :)~

Leona [35]3 years ago
6 0

Step-by-step explanation:

i work in paper sheet please see it

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vaieri [72.5K]

Answer:

L = 11 m

Step-by-step explanation:

The perimeter is 40 m, which in turn equals 2L + 2W.  With W = 9 m, we have:

40m = 2L + 2(9 m), or   40 m = 2L + 18 m, or 22 m = 2L.  Then L = 11 m.


4 0
4 years ago
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4 0
3 years ago
Find the nth term for the<br> following sequences:<br> Q2)3, 9, 15, 21
elixir [45]

Answer:

a_{n} = 6n - 3

Step-by-step explanation:

There is a common difference d between consecutive terms, that is

d = 9 - 3 = 15 - 9 = 21 - 15 = 6

This indicates the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 3 and d = 6, then

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6 0
3 years ago
What is the common difference for the arithmetic sequence? -6, -1, 4, 9, 14​
denpristay [2]

Answer:

5

Step-by-step explanation:

The common difference of any arithmetic sequence is the difference between two consecutive terms in the sequence.

In the provided sequence

-1-(-6)=5

4-(-1)=5

9-4=5

14-9=5

Therefore the common difference, d=5

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3 years ago
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If you're referring to the actual 3D shape, that would be a rectangle. If you're referring to the shape in the middle, it would be a Trapezoid.

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3 years ago
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