Following the graph as listed we can immidiately say that (1/2,-2) & (-2,-8) must be wrong. This can be seen by the fact that the line's don't intersect in quadrants 1 & 4. It also cannot be greater than -2 or y would not =-2. Thus it must be (-1/2,-2) or (-2,1/2) and because we know they don't intersect in quadrant two, t<u>he correct answer must be (-1/2,-2)</u>. So the last answer is correct for the intersection point.
<em>TLDR: (-1/2,-2) is the correct answer. </em>
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A) 3 centerpieces per hour because 15/5 = 3
b) 14 hours, because 3 goes into 42 14 times exactly.
Hope this helps!
Given :-
- The general term of a sequence is given by aₙ=43-3(n-1) .
To Find :-
- The first four terms of the sequence.
Solution :-
The given expression is 
→ aₙ=43-3(n-1)
where n > 0
<u>Finding</u><u> the</u><u> </u><u>first </u><u>term </u><u>:</u>
Substituting n = 1 , we have ,
→ T1 = 43 - 3(1-1)
→ T1 = 43 - 3*0
→ T1 = 43 - 0 = 43
<u>Finding</u><u> the</u><u> </u><u>second</u><u> </u><u>term </u><u>:</u>
Substituting n = 2 , we have,
→ T2 = 43 -3(2-1)
→ T2 = 43 -3*1
→ T2 = 43 -3 = 40
<u>Finding</u><u> </u><u>the </u><u>third </u><u>term</u><u> </u><u>:</u>
Substituting n = 3 , we have,
→ T3 = 43 -3(3-1)
→ T3 = 43 -3*2
→ T3 = 43 -6 = 37
<u>Finding</u><u> the</u><u> </u><u>fourth</u><u> </u><u>term </u><u>:</u>
→ T4 = 43 -3(4-1)
→ T4 = 43 -3*3
→ T4 = 43-9 = 34
<u>Hence</u><u> the</u><u> </u><u>first</u><u> </u><u>four</u><u> terms</u><u> of</u><u> </u><u>the</u><u> </u><u>sequence</u><u> </u><u>are </u><u>4</u><u>3</u><u> </u><u>,</u><u> </u><u>4</u><u>0</u><u> </u><u>,</u><u> </u><u>37</u><u> </u><u>and </u><u>34</u><u> </u><u>.</u>
<em>I </em><em>hope</em><em> this</em><em> helps</em><em> </em><em>.</em><em> </em><em>Let </em><em>me</em><em> know</em><em> if</em><em> you</em><em> </em><em>need </em><em>further</em><em> </em><em>clarification</em><em> </em><em>.</em>
10 ÷(-5)= -2
The answer is A
Answer:

This will give 5 Students each in 12 different equally sized groups

This also shows that students can grouped in equal groups of 12 in 5 places
Step-by-step explanation:
From the question we are told that
60 children in equal sized groups
Generally interpreting
can be mathematically represented as
a)


This will give 5 Students each in 12 different equally sized groups
b)


This also shows that students can grouped in equal groups of 12 in 5 places