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3241004551 [841]
3 years ago
14

Calling the math genusis over here !! I need this question answered plz .

Mathematics
2 answers:
Ivahew [28]3 years ago
8 0
Y-intercept is (0,4)

Hope this helped!
Salsk061 [2.6K]3 years ago
3 0

Answer: The y intercept is 4

It is located at the point (0, 4)

==============================================================

Explanation:

The y intercept is where the graph crosses the vertical y axis. This happens at 4 on the y axis. We can get more specific to say the location is (x,y) = (0,4). Though we could go for the shorter form because all y intercepts occur when x = 0.

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The diagram shows two straight lines. both lines intersect at point A.
Setler [38]

Following the graph as listed we can immidiately say that (1/2,-2) & (-2,-8) must be wrong. This can be seen by the fact that the line's don't intersect in quadrants 1 & 4. It also cannot be greater than -2 or y would not =-2. Thus it must be (-1/2,-2) or (-2,1/2) and because we know they don't intersect in quadrant two, t<u>he correct answer must be (-1/2,-2)</u>. So the last answer is correct for the intersection point.

<em>TLDR: (-1/2,-2) is the correct answer. </em>

<em />

6 0
3 years ago
You create 15 centerpieces for a party in 5 hours.
barxatty [35]
A) 3 centerpieces per hour because 15/5 = 3
b) 14 hours, because 3 goes into 42 14 times exactly.
Hope this helps!
7 0
3 years ago
Find the first four terms of the sequence given by the following.<br> aₙ=43-3(n-1) n=1,2,3. . .
Serggg [28]

Given :-

  • The general term of a sequence is given by aₙ=43-3(n-1) .

To Find :-

  • The first four terms of the sequence.

Solution :-

The given expression is /

→ aₙ=43-3(n-1)

where n > 0

<u>Finding</u><u> the</u><u> </u><u>first </u><u>term </u><u>:</u>

Substituting n = 1 , we have ,

→ T1 = 43 - 3(1-1)

→ T1 = 43 - 3*0

→ T1 = 43 - 0 = 43

<u>Finding</u><u> the</u><u> </u><u>second</u><u> </u><u>term </u><u>:</u>

Substituting n = 2 , we have,

→ T2 = 43 -3(2-1)

→ T2 = 43 -3*1

→ T2 = 43 -3 = 40

<u>Finding</u><u> </u><u>the </u><u>third </u><u>term</u><u> </u><u>:</u>

Substituting n = 3 , we have,

→ T3 = 43 -3(3-1)

→ T3 = 43 -3*2

→ T3 = 43 -6 = 37

<u>Finding</u><u> the</u><u> </u><u>fourth</u><u> </u><u>term </u><u>:</u>

→ T4 = 43 -3(4-1)

→ T4 = 43 -3*3

→ T4 = 43-9 = 34

<u>Hence</u><u> the</u><u> </u><u>first</u><u> </u><u>four</u><u> terms</u><u> of</u><u> </u><u>the</u><u> </u><u>sequence</u><u> </u><u>are </u><u>4</u><u>3</u><u> </u><u>,</u><u> </u><u>4</u><u>0</u><u> </u><u>,</u><u> </u><u>37</u><u> </u><u>and </u><u>34</u><u> </u><u>.</u>

<em>I </em><em>hope</em><em> this</em><em> helps</em><em> </em><em>.</em><em> </em><em>Let </em><em>me</em><em> know</em><em> if</em><em> you</em><em> </em><em>need </em><em>further</em><em> </em><em>clarification</em><em> </em><em>.</em>

7 0
2 years ago
What is the quotient 10 ÷ (-5)?<br> A) -2 <br> B) 2 <br> C) -12<br> D) 12
Degger [83]
10 ÷(-5)= -2

The answer is A
7 0
3 years ago
During a field trip, 60 students are put into equal-sized groups. Describe two ways to interpret 60 ÷ 5 in this problem *
sergeinik [125]

Answer:

    x=12 groups

This will give 5 Students each in 12 different equally sized groups

    x'=5groups

This also shows that students can grouped in equal groups of 12 in 5 places

Step-by-step explanation:

From the question we are told that

60 children in equal sized groups

Generally interpreting 60\div 5 can be mathematically represented as

a)

    x=\frac{60}{5}

    x=12 groups

This will give 5 Students each in 12 different equally sized groups

b)

    x'=\frac{60}{12}

    x'=5groups

This also shows that students can grouped in equal groups of 12 in 5 places

6 0
3 years ago
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