Answer:
14,850
Step-by-step explanation:
You need the sum of
3 + 6 + 9 + 12 + ... + 294 + 297
Factor out a 3 from the sum
3 + 6 + 9 + 12 + ... + 294 + 297 = 3(1 + 2 + 3 + 4 + ... + 98 + 99)
You need to add all integers from 1 to 99 and multiply by 3.
The sum of all consecutive integers from 1 to n is:
[n(n + 1)]/2
The sum of all consecutive integers from 1 to 99 is
[99(99 + 1)]/2
The sum you need is 3 * [99(99 + 1)]/2
3 + 6 + 9 + 12 + ... + 294 + 297 =
= 3 * [99(99 + 1)]/2
= 3 * [99(100)]/2
= 3 * 9900/2
= 14,850
Answer:
its the math that solve
Step-by-step explanation:
If you're going to ask for help, you may as well ask for help from an app designed for the purpose. This app is available for both Android and iOS devices. My TI-83/84 calculator also has a triangle solver app.
(A) There is only one possible solution
b = 16.3
C = 26°
B = 87°
_____
If you want to do this yourself, you can use the Law of Sines to find angle C.
.. C = arcsin(7.1/15*sin(67°)) ≈ 25.8302° . . . . don't round intermediate values
Then angle B is 180° -67° -angle C = 87.1698°
and side b is found from the Law of Sines:
.. b = 15*sin(C)/sin(A) ≈ 16.2755
Answer:

Step-by-step explanation:
Given the expression ![\frac{\sqrt[5]{b} }{\sqrt[]{b} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B5%5D%7Bb%7D%20%7D%7B%5Csqrt%5B%5D%7Bb%7D%20%7D)
![\frac{\sqrt[5]{b} }{\sqrt[]{b} } \\= \frac{b^{1/5}}{b^{1/2}} \\= b^{1/5-1/2}\\= b ^{2-5/10}\\= b^{-3/10}\\Compare \ b^n \ with \ b^{-3/10}\\\\n = -3/10](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B5%5D%7Bb%7D%20%7D%7B%5Csqrt%5B%5D%7Bb%7D%20%7D%20%5C%5C%3D%20%5Cfrac%7Bb%5E%7B1%2F5%7D%7D%7Bb%5E%7B1%2F2%7D%7D%20%5C%5C%3D%20b%5E%7B1%2F5-1%2F2%7D%5C%5C%3D%20b%20%5E%7B2-5%2F10%7D%5C%5C%3D%20b%5E%7B-3%2F10%7D%5C%5CCompare%20%5C%20b%5En%20%5C%20with%20%5C%20%20b%5E%7B-3%2F10%7D%5C%5C%5C%5Cn%20%3D%20-3%2F10)
The missing factor is 20. 10 x 20 = 200