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SashulF [63]
3 years ago
13

May anyone help me with this?

Mathematics
1 answer:
Verdich [7]3 years ago
5 0

Answer:

31

Step-by-step explanation:

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A vehicle originally travelled at 30 kph. Now its speed is increased to 10 kph more than twice its original speed. What is the s
Helen [10]

Answer:

20kph

Step-by-step explanation:

10 * 2 = 20

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Which of the following pair of right triangles cannot be proven to be congruent? Select all that apply.
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The equation T^2 = A^3 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun,
Helen [10]

So, let planet X's orbital period be T and its mean distance from the sun be A. Also let planet Y's orbital period be T_1, so that means if planet Y's mean distance from the sun were double that of planet X:

Z^2=(2A)^3\\ Z^2=8A^3\implies\\ Z^2=8T^2 \implies\\ Z=2\sqrt{2}T

Which means that the orbital period in planet Y is increased by a factor of 2\sqrt{2}

4 0
3 years ago
(X-2) is a factor of x^4+2x^3-7x^2-8x+12. The other factors are ____, ____, and _____
Vika [28.1K]

We have

\dfrac{x^4+2x^3-7x^2-8x+12}{x-2}=x^3+4x^2+x-6

The rational root theorem suggests that other possible roots may be -6, 6, -3, 3, -2, 2, -1, and 1. It turns out that x=-2 is a root, since (-2)^3+4(-2)^2+(-2)-6=0, so x+2 is also a factor and we have

\dfrac{x^4+2x^3-7x^2-8x+12}{(x-2)(x+2)}=x^2+2x-3

Finally, we can factorize the remaining quotient easily:

x^2+2x-3=(x+3)(x-1)

so the other factors are x+2, x+3, and x-1.

5 0
4 years ago
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