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uranmaximum [27]
3 years ago
11

Identify one exterior angle. Help please

Mathematics
1 answer:
Serggg [28]3 years ago
3 0
Angle 1, 3, and 5 are exterior angles.
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A blueprint for a house states that 2.5 inches equals 10 feet. If the length of a wall is 12 ft , how many inches is the wall in
tankabanditka [31]

Answer:

3 inches

Step-by-step explanation:

2.5 inches = 10 feet

x inches.   = 12 feet

Solve as a proportion

2.5(12) = 10x

30=10x

3=x

3 inches

6 0
3 years ago
Work out 19% of 394.22​
saveliy_v [14]

Answer:

74.9018

Step-by-step explanation:

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6 0
3 years ago
Find the slope of the following graph and Choose the correct result
-BARSIC- [3]

Answer: B 1/3

Step-by-step explanation:

For every 3x it travels 1 y so you will get 1/3 as your answer.

At 50y the line is at 10x.  By the time it is at 60 y it is at 40x.  This was a change in y by 10 and change in x by 30.  There fore the answer is 10/30 or 1/3.

3 0
3 years ago
Read 2 more answers
A circle has the order pairs (-1, 2) (0, 1) (-2, -1) what is the equation . Show your work.
olga55 [171]
We know that:

(x-a)^2+(y-b)^2=r^2

is an equation of a circle.

When we substitute x and y (from the pairs we have), we'll get a system of equations:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}

and all we have to do is solve it for a, b and r.

There will be:

\begin{cases}(-1-a)^2+(2-b)^2=r^2\\(0-a)^2+(1-b)^2=r^2\\(-2-a)^2+(-1-b)^2=r^2\end{cases}\\\\\\
\begin{cases}1+2a+a^2+4-4b+b^2=r^2\\a^2+1-2b+b^2=r^2\\4+4a+a^2+1+2b+b^2=r^2\end{cases}\\\\\\
\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\\\\\


From equations (II) and (III) we have:

\begin{cases}a^2+b^2-2b+1=r^2\\a^2+b^2+4a+2b+5=r^2\end{cases}\\--------------(-)\\\\a^2+b^2-2b+1-a^2-b^2-4a-2b-5=r^2-r^2\\\\-4a-4b-4=0\qquad|:(-4)\\\\\boxed{-a-b-1=0}

and from (I) and (II):

\begin{cases}a^2+b^2+2a-4b+5=r^2\\a^2+b^2-2b+1=r^2\end{cases}\\--------------(-)\\\\a^2+b^2+2a-4b+5-a^2-b^2+2b-1=r^2-r^2\\\\2a-2b+4=0\qquad|:2\\\\\boxed{a-b+2=0}

Now we can easly calculate a and b:

\begin{cases}-a-b-1=0\\a-b+2=0\end{cases}\\--------(+)\\\\-a-b-1+a-b+2=0+0\\\\-2b+1=0\\\\-2b=-1\qquad|:(-2)\\\\\boxed{b=\frac{1}{2}}\\\\\\\\a-b+2=0\\\\\\a-\dfrac{1}{2}+2=0\\\\\\a+\dfrac{3}{2}=0\\\\\\\boxed{a=-\frac{3}{2}}

Finally we calculate r^2:

a^2+b^2-2b+1=r^2\\\\\\\left(-\dfrac{3}{2}\right)^2+\left(\dfrac{1}{2}\right)^2-2\cdot\dfrac{1}{2}+1=r^2\\\\\\\dfrac{9}{4}+\dfrac{1}{4}-1+1=r^2\\\\\\\dfrac{10}{4}=r^2\\\\\\\boxed{r^2=\frac{5}{2}}

And the equation of the circle is:

(x-a)^2+(y-b)^2=r^2\\\\\\\left(x-\left(-\dfrac{3}{2}\right)\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}\\\\\\\boxed{\left(x+\dfrac{3}{2}\right)^2+\left(y-\dfrac{1}{2}\right)^2=\dfrac{5}{2}}
7 0
3 years ago
A rectangular prism with a length of 3.8 meters and a width of 1.5 meters has a volume of 16.53 cubic meters.
Maslowich

Answer:

H = 2.9  m

Step-by-step explanation:

Volume =   L x W x H

                 3.8 x 1.5  x H = 16.53

                     H = 16.53 / (3.8 x 1.5)  = 2.9 m

7 0
2 years ago
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