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3 years ago

Can someone show me what is 5% of 34 and show me how to breakdown the equation?

Mathematics

1 answer:

vesna_86 [32]3 years ago

4 0

The answer for this problem is 1.7 I think I’m not sure

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Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 1/2

siniylev [52]

<u>Answer:</u> The probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

<u>Step-by-step explanation:</u>

We are given:

Probability of success of Xavier, $P(S)_{Xavier}=\frac{1}{4}$

Probability of failure of Xavier, $P(F)_{Xavier}=1-\frac{1}{4}=\frac{3}{4}$

Probability of success of Yvonne, $P(S)_{Yvonne}=\frac{1}{2}$

Probability of failure of Yvonne, $P(F)_{Yvonne}=1-\frac{1}{2}=\frac{1}{2}$

Probability of success of Zelda, $P(S)_{Zelda}=\frac{5}{8}$

Probability of failure of Zelda, $P(F)_{Zelda}=1-\frac{5}{8}=\frac{3}{8}$

We need to calculate:

The probability that Xavier and Yvonne can solve the problem but Zelda cannot, we use:

$P(S)_{Xavier}\times P(S)_{Yvonne}\times P(F)_{Zelda}=\frac{1}{4}\times \frac{1}{2}\times \frac{3}{8}=\frac{3}{64}$

Hence, the probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

6 0

3 years ago

There are 7 playing cards in a bag. 1 of those cards is a spade.

Marianna [84]

1/7 is the answer to your question

6 0

3 years ago

Read 2 more answers

I need help with this

Lady bird [3.3K]

I believe the answer to this is "If they babysit for 5 hours, Jayna will earn more" because Hannah charages 7$ an hour and Jayna charges 10$ an hour so Jayna will have more money than Hannah in five hours.

4 0

4 years ago

Karina is creating two pyramids with the nets below using construction paper. In both nets, all of the triangular faces of the p

sleet_krkn [62]

Answer:

144 sq in

Step-by-step explanation:

Face height=9, bases=6 in

#Assume the pyramid has a square base.

First we need to calculate the perpendicular height of the pyramid:

$#Pythagorean \ Theorem\\a^2+b^2=c^2\\9^2-(0.5\times 6)^2=h^2\\72=h^2\\h=\sqrt{72} \ in$

Now to find the surface area of each pyramid:

$A=lw+l\sqrt{(w/2)^2+h^2}+w\sqrt{(l/w)^2+h^2}\\\\\#w=l=6,h=\sqrt{72}\\\\A=6^2+6\sqrt{(6/2)^2+72}+6\sqrt{(6/6)^2+72}\\\\A\approx 144\ sq \ in$

Hence amount of construction paper needed to make each pyramid is 144 sq in

3 0

3 years ago

10. My numerator is a prime number. The GCF of my numerator and

frutty [35]

Answer:

The answer is 5/25

Step-by-step explanation:

6 0

4 years ago

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