The answer to your question is <span>B.-2/3</span>
Given:
8 2/3 hours per month
12 months in a year.
Number of hours she play soccer in a year.
8 2/3 must be converted to improper fraction.
((8*3)+2)/3 = 26/3
26/3 * 12 = (26 * 12)/3 = 312/3 = 104
Yolanda spends 104 hours in a year playing soccer.
Answer:
I believe it would be B) Reflection, then translation
Step-by-step explanation:
Answer:
A. Law of detachment
Step-by-step explanation:
The Law of detachment implies that when one condition is fulfilled the other cannot be and vice versa, then it is made the conclusion.
This condition is made the conclusion.
The Acute and Obtuse are detached of each other.
The acute angle is one in which the value of the angle is less than 90 degrees and obtuse angle is one in which the angle is greater than 90 degrees but less than 180 degrees.
Thus angles less than 90 degrees are acute and greater than 90 degrees are obtuse.
The conclusion of the given statement is valid based on the law of detachment as the condition has been made a conclusion.
Answer:
198 cubic metres
Steps:
<em><u>Find </u></em><em><u>the </u></em><em><u>area </u></em><em><u>of </u></em><em><u> </u></em><em><u>cross</u></em><em><u> </u></em><em><u>section</u></em>
<em><u>Area </u></em><em><u>if </u></em><em><u>traing</u></em><em><u>l</u></em><em><u>e </u></em><em><u>+</u></em><em><u> </u></em><em><u>Area </u></em><em><u>of </u></em><em><u>square</u></em>
<em><u>1</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>4</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>4</u></em><em><u>×</u></em><em><u>4</u></em>
<em><u>6</u></em><em><u>+</u></em><em><u> </u></em><em><u>1</u></em><em><u>6</u></em>
<em><u>2</u></em><em><u>2</u></em>
<em><u>Then </u></em><em><u>times </u></em><em><u>with </u></em><em><u>the </u></em><em><u>lenght </u></em><em><u>(</u></em><em><u>9</u></em><em><u>)</u></em>
<em><u>2</u></em><em><u>2</u></em><em><u>×</u></em><em><u>9</u></em>
I hope this helps, dont hesitate to ask for any question.
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