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3 years ago

HELP. car takes 10 hour and 30 minutes from A to B point. how many hours will it take for car if it's speed increases 1.2 times?

Mathematics

1 answer:

amm18123 years ago

7 0

9514 1404 393

Answer:

8 3/4 hours

Step-by-step explanation:

Time is inversely proportional to speed for the same distance. The time for 1.2 times the speed will be 1/1.2 times the given time:

(10.5 h)/1.2 = 8.75 h

It will take 8.75 hours at the increased speed.

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Create a list of six values where the mean, median, and mode are 45, and only two of the values are the same.

tresset_1 [31]

10 30 45 45 48 55, 55-10=45=mode median and mean
Hope this helps

6 0

3 years ago

Solve 2x-3< 2<br>please answer it fast

murzikaleks [220]

Answer:

x<5/2

Step-by-step explanation:

We have

2x−3<2

Add 3 to both sides.

2x−3 +3 <2 +3

which makes

2x<5

Divide both sides by 2.

2x/2 < 5/2

x<5/2

4 0

3 years ago

Please answer math question

slavikrds [6]

Answer:

y = -4x + 9

O.R. y = 9- 4x

(both answers are equivalent, the same)

Step-by-step explanation:

1. finding gradient of perpendicular line to the equation given.

2. use the point provided in the wuestion and substitute it into the linear form of your slope-intercept form, which in my country is called the linear form, meaning straight line graph.

3. get answers by finding the y-intercept of the equation wanted.

note:

y = mx + c is how and what i use in my school as the linear form, altho every school is different and I understand that, so do check again with your teacher if it is how you do such type of questions.

5 0

3 years ago

Find a quadratic polynomial the sum and product of whose zeroes are -8 and 12 respectively. Hence find the zeroes.

Olenka [21]

Step-by-step explanation:

We khow the sum and the product of the zeroes of this quadratic polynomial

Here is a trick :

when we khow the sum S and the product P ofvtwo numbers we can find them by solving :

x²-Sx+p=0

here S= -8 and P=12

so:

x²+8x+12=0

Let Δ be the discrminant of this equation: a= 1 , b= 8 and c=12

Δ= 8²-4*12 =16

the zeros are:

(-8-4)/2= -6

(-8+4)/2 = -2

verify:

-6+(-2)= -8

-2*(-6)= 12

now the polynomial quadratic is:

(x+6)(x+2)

7 0

3 years ago

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago