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dusya [7]
2 years ago
9

A wind turbine has a capacity of 3 mw

Advanced Placement (AP)
2 answers:
Artemon [7]2 years ago
6 0

Answer:

How many watts does a wind turbine produce?

The output of a wind turbine depends on the turbine's size and the wind's speed through the rotor. An average onshore wind turbine with a capacity of 2.5–3 MW can produce more than 6 million kWh in a year – enough to supply 1,500 average EU households with electricity.

Explanation:

Svetradugi [14.3K]2 years ago
3 0
The output of a wind turbine depends on the turbine's size and the wind's speed through the rotor. An average onshore wind turbine with a capacity of 2.5–3 MW can produce more than 6 million kWh in a year
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Ano ang maitutulong upang magkaroon ng ekwilibriyo ang pamilihan​
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Answer:

Kailangan isa puso at isa isip na kailangan ang masinop na paggmiat ng pinagkukunan upang maiwasan ang kakulangan na magsasanhi ng disekwilibriyo. Nasa mamamayan ang kapangyarihan upang  mapanatili ang maayos na ekwilibriyong presyo at dami sa pamilihan.

Explanation:

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Answer:

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3 years ago
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The regions bounded by the graphs of y=x2 and y=sin2x are shaded in the figure above. What is the sum of the areas of the shaded
Alex Ar [27]

Answer:

The sum of the area of the shaded regions = 0.248685

Explanation:

The sum of the area of the shaded region is given as follows;

The point of intersection of the graphs are;

y = x/2

y = sin²x

∴ At the intersection, x/2 = sin²x

sinx = √(x/2)

Using Microsoft Excel, or Wolfram Alpha, we have that the possible solutions to the above equation are;

x = 0, x ≈ 0.55 or x ≈ 1.85

The area under the line y = x/2, between the points x = 0 and x ≈ 0.55, A₁, is given as follows

1/2 × (0.55)×0.55/2 ≈ 0.075625

The area under the line y = sin²x, between the points x = 0 and x ≈ 0.55, A₂, is given using as follows;

\int\limits {sin^n(x)} \, dx = -\dfrac{1}{n} sin^{n-1}(x) \cdot cos(x) + \dfrac{n-1}{n} \int\limits {sin^{n-2}(x)} \, dx

Therefore;

A_2 = \int\limits^{0.55}_0 {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_0 ^{0.55}

∴ A₂ =1/2 × ((0.55 - sin(0.55)×cos(0.55)) - (0 - sin(0)×cos(0)) ≈ 0.0522

The shaded area, A_{1 shaded} = A₁ - A₂ = 0.075625 - 0.0522 ≈ 0.023425

Similarly, we have, between points 0.55 and 1.85

A₃ = 1/2 × (1.85 - 0.55) × 1/2 × (1.85 - 0.55) + (1.85 - 0.55) × 0.55/2 = 0.78

For y = sin²x, we have;

A_4 = \int\limits^{1.85}_{0.55} {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_{0.55} ^{1.85} \approx 1.00526

The shaded area, A_{2 shaded} = A₄ - A₃ = 1.00526 - 0.78 ≈ 0.22526

The sum of the area of the shaded regions, ∑A = A_{1 shaded} + A_{2 shaded}

∴ A = 0.023425 + 0.22526 = 0.248685

The sum of the area of the shaded regions, ∑A = 0.248685

8 0
3 years ago
How does Madison use comparison to bolster his argument?
DochEvi [55]

The correct answer to this open question is the following.

You do not include any reference to what argument, text, or paper written by James Madison, because he wrote many as part of the authors of the Federalists papers.

However, probably you are referring to "Federalist N.-10." If this is the case, then the correct answer is the following.

Madison used the comparison to bolster his argument in that he compares two forms of government: Republic and Pure Democracy. In that comparison, James Madison says that the wrongdoings and failures of Pure Democracy represent the benefits of a Republic. So he tries to promote the idea of a Republic as the new form of government for the new nation.  

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