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DedPeter [7]
2 years ago
5

List some of the valid reasons that can be used in a proof:

Mathematics
2 answers:
Genrish500 [490]2 years ago
8 0

Answer:

Experiment results, and more results!

They help a LOT!

Step-by-step explanation:

Virty [35]2 years ago
5 0
Experiment results and risks
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Suppose you cut along a diagonal of a rhombus, a rectangle, or a square. Would you get two triangles that have the same shape an
stich3 [128]
I believe the answer to your question is 

Yes, you would get two triangles that have the same shape and size
3 0
3 years ago
An investment fund grows at a rate of 17%, once a year. Yahya puts $1,000 in the account as the principal. How can Yahya set up
Ira Lisetskai [31]

Answer:

Step-by-step explanation:

8 0
3 years ago
Which is greater 11/16 or 3/4
Anettt [7]
To compare fractions, we need to have the same denominator
The least common multiple is 16
\frac{11}{16} 
to change \frac{3}{4}, we should multiply the numerator and denominator by 4
\frac{3*4}{4*4} = \frac{12}{16}

\frac{11}{16} < \frac{12}{16}

so basically, \frac{12}{16} is greater than \frac{11}{16}
which means \frac{3}{4} is greater

\frac{3}{4} is greater
6 0
3 years ago
In a certain Algebra 2 class of 30 students, 14 of them play basketball and 10 of them play baseball. There are 14 students who
Veseljchak [2.6K]

Answer:

In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.

But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?

Thank you for all of the help.

That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)

So: the two events are not independent, and so that formula doesn't work.

Fortunately, a formula that does work (always!) is:

P(A∪B)=P(A)+P(B)−P(A∩B)

Hence:

P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330

7 0
3 years ago
A man has two more nickels than dimes. He has $1.15 in all. How many coins of each kind does he have?
zhannawk [14.2K]

Answer:

Man has 9 Nickels and 7 dimes.

Step-by-step explanation:

Let Number of dimes be x

and Number of Nickels be y

As Per given data he has two more nickels than dimes.

y= 2+x\\

As we know that

1\$ = 100 cent

1 nickel is worth = 5 cents = \frac{5}{100}= 0.05\$

1 dime is worth = 10 cents = \frac{10}{100} 0 .1\ $

According to given data he has \$\ 1.15 total nickel and dimes

So the equation becomes,

0.05y+0.1x=1.15

but y= 2+x

0.05(2+x)+0.1x=1.15\\0.1+0.05x+0.1x=1.15\\0.1+0.15x= 1.15\\0.15x= 1.15-0.1\\0.15x=1.05\\x=\frac{1.05}{0.15}= 7

Substituting value of x in equation y = 2+x we get

y= 2+7 =9

Man has 9 Nickels and 7 dimes.

5 0
3 years ago
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