3rd option.
at least shows that the number can be equal to 2, and also that 2 should be the smallest possible value of the number.
Answer:
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Step-by-step explanation:
For the first one:

you change the subtract 2 to add 2 on both sides. so it looks like the picture above. Then you would add 20 + 2 to equal 22. Then you divide that by 1 (from the t). that equals 22, so thats the answer.
GIVEN :
a = 1/√10 ( 3i + k) and
b = 1/7 ( 2i + 3j - 6k)
TO FIND :
( 2a- b) . [ ( a x b ) x ( a + 2b)]
SOLUTION :
◆Going with the equation given,
( 2a - b) . [ ( a x b ) x ( a + 2b)]
= (2a - b) [( a×b×a) + 2(a×b)×b]
◆BAC - CAB RULE,
A×B×C = B( A.B ) - C(A.B )
= (2a- b ) [ (b (a.a ) - a (a.b ) + 2b ( a.b) -2b (a.b]
Solving further
= (2a - b )(b - 2a)
= -4a.a -b.b
=-5.
Answer:
( 2 - b) . [ ( a x b ) x ( a + 2b)] = -5
Hoped I helped