Answer:
y = 10852 bacteria
Step-by-step explanation:
The equation is exponential growth
y = a b^x where a is the initial amount , b is the growth rate and x is the time
At time 0, we have 5000 bacteria
5000 = a * b^0
5000 = a *1
a = 1
At 4 hours, we have 6000 bacteria
6000 = 5000 * b^4
Divide each side by 5000
6000/5000 = b^4
6/5 = b^4
Take the 4th root of each side
(6/5)^(1/4) = (b^4)^(1/4)
1.046635139 = b
Our equation is
y = 5000 (1.046635139) ^ x
We want to find the number of bacteria present after 17 hours
y = 5000 (1.046635139)^17
y=10851.51313
To the nearest whole number
y = 10852 bacteria
Answer:
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Step-by-step explanation:
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Answer:
48f^2-110f+63
Step-by-step explanation:
We multiple every part of first sum with every prt of the 2nd sum:
(6f-7)(8f-9)=48f^2-54f-56f+63=
48f^2-110f+63
Answer:
<em>Since the profit is positive, Rebotar not only broke even, they had earnings.</em>
Step-by-step explanation:
<u>Function Modeling</u>
The costs, incomes, and profits of Rebotar Inc. can be modeled by means of the appropriate function according to known conditions of the market.
It's known their fixed costs are $3,450 and their variable costs are $12 per basketball produced and sold. Thus, the total cost of Rebotar is:
C(x) = 12x + 3,450
Where x is the number of basketballs sold.
It's also known each basketball is sold at $25, thus the revenue (income) function is:
R(x) = 25x
The profit function is the difference between the costs and revenue:
P(x) = 25x - (12x + 3,450)
Operating:
P(x) = 25x - 12x - 3,450
P(x) = 13x - 3,450
If x=300 basketballs are sold, the profits are:
P(300) = 13(300) - 3,450
P(300) = 3,900 - 3,450
P(300) = 450
Since the profit is positive, Rebotar not only broke even, they had earnings.
