We have that
3 = 3 + 0i -----------> rewrite as 3(1 + 0i)
<span>So now what we have to do is figure out which of the above expressions has cos a = 1 and sin a = 0. </span>
<span>cos 0 = 1, and sin 0 = 0, so that's the answer that we want.
</span><span>the answer is: </span>
3 = 3(cos 0 + i sin 0)
In this case, you have to find a common multiple of 3a^2 and 4ab. As only one of the numbers is divisible by two, this means that two cannot go outside of the bracket. The only other aspect that is in both sides of the equation is a, therefore, this goes outside the bracket. The best way to approach this is to divide both sides by a, and this will give you what is inside the bracket. 3a^2 divided by a is 3a, therefore, this is the first aspect in the bracket. -4ab divided by a, leaves -4b. Therefore, these go in the bracket.
3a^2- 4ab simplified is a(3a-4b)
Hope this helps
In a 30°-60°-90° triangle, the ratio of the legs is
So if the shorter leg is
, then the longer leg is
f'(x) = - 6
hence f'(1) = - 6
f'(x) = - 6 for all real values of a
