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8_murik_8 [283]
3 years ago
8

Which term describes gross pay that is calculated based on the number of hours an employee has worked?

Mathematics
2 answers:
statuscvo [17]3 years ago
8 0

Answer: Hourly wage

Step-by-step explanation:

The term "hourly wage" describes the gross pay that is calculated based on the number of hours an employee has worked.

The hourly wage is the amount of money that is earned by a employee for every hour worked or it is the amount of money paid by employer for every hour worked.

Here, the gross pay is calculated by multiplying the hourly wage to the number of hours worked.

frosja888 [35]3 years ago
4 0
The term for this is Hourly wage. This can be then used for calculating the gross annual salary.

hope this helps you.
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Supplementary angles. They both add up to equal 180 degrees
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I NEED HELP ASAP IT'S DUE IN 10 MINUTES!!! I'LL GIVE BRAINLIEST!!!
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Moises is determining the solution to the system of equations that is show below. Equation representing line A: mc018-1.jpg Poin
dimulka [17.4K]
Answer:
equation of line is:
y = -2x - 6

Explanation:
The general form of the line is:
y = mx + c
where:
m is the slope of the line
c is the y-intercept

(a) getting the slope of the line:
slope of the line is calculated using the following rule:
slope of line (m) = (y2-y1) / (x2-x1) = (-24--12) / (9-3) = -2
The equation now becomes:
y = -2x + c

(b) getting the y-intercept:
The two given points belong to the line. Therefore, to get the y-intercept, we will use one of the points and substitute in the equation and solve for c.
I will use the point (3,-12)
y = mx + c
-12 = -2(3) + c
-12 = -6 + c
c = -12 + 6
c = -6

Based on the above, the equation of the line is:
y = -2x - 6

Hope this helps :)
6 0
3 years ago
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Let φ(x, y) = arctan (y/x) .
Alexandra [31]

Answer:

a) \large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})

b) \large \mathbb{R}^2-\{(0,0)\}

c) the points of the form (x, -x) for x≠0

Step-by-step explanation:

a)

If φ(x, y) = arctan (y/x), the vector field F = ∇φ would be

\large F(x,y)=(\frac{\partial \phi}{\partial x},\frac{\partial \phi}{\partial y})

On one hand we have,

\large \frac{\partial \phi}{\partial x}=\frac{\partial arctan(y/x)}{\partial x}=\frac{-y/x^2}{1+(y/x)^2}=-\frac{y/x^2}{1+y^2/x^2}=\\\\=-\frac{y/x^2}{(x^2+y^2)/x^2}=-\frac{y}{x^2+y^2}

On the other hand,

\large \frac{\partial \phi}{\partial y}=\frac{\partial arctan(y/x)}{\partial y}=\frac{1/x}{1+(y/x)^2}=\frac{1/x}{1+y^2/x^2}=\\\\=\frac{1/x}{(x^2+y^2)/x^2}=\frac{x}{x^2+y^2}

So

\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})

b)

The domain of definition of F is  

\large \mathbb{R}^2-\{(0,0)\}

i.e., all the plane X-Y except the (0,0)

c)

Here we want to find all the points such that

\large (-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})=(k,k)

where k is a real number other than 0.

But this means

\large -\frac{y}{x^2+y^2}=\frac{x}{x^2+y^2}\Rightarrow y=-x

So, all the points in the line y = -x except (0,0) are parallel to the vector field F, that is, the points (x, -x) with x≠ 0

8 0
3 years ago
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