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seropon [69]
3 years ago
12

What is the area of the trapezoid below?

Mathematics
1 answer:
goldenfox [79]3 years ago
5 0

Answer:

Area 684 m squared

Step-by-step explanation:

26 + 46 = 72

72/2 = 36

36 x 19 = 684

Hope this helps!

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Solve the system of linear equations by substitution. x=17−4y y=x−2
erik [133]

Answer:

y = x - 2

x = 17 - 4y

x = 17 - 4(x -2)

x = 17 - 4x + 8

5x = 17 + 8

5x = 25

x = 5

y = 5 - 2

y = 3

(5, 3)

Step-by-step explanation:

7 0
4 years ago
Maria incorrectly placed the decimal point when she wrote 0.65 inch fo the width of her computer. what is the correct decimal nu
Anit [1.1K]
I think it should be 6.5 inch but I'm not positive.

I hope this helps! :))
5 0
4 years ago
Read 2 more answers
A group of students estimated the length of one minute without reference to a watch or​ clock, and the times​ (seconds) are list
alexandr402 [8]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

Yes the students are reasonably good at estimating one​ minute

a

  Option A is  correct

b

  The test statistics is  t  =  0.354

Step-by-step explanation:

From the question we are told that

    The  set of data is  

               68, 82 ,  38 ,  62 , 41, 25 , 57 ,  64, 67, 47, 61, 71, 91, 87, 64

     The  population mean is  \mu  = 60

The  level of significance is given as\alpha =  0.01

    The  critical value for this level of significance obtained from the normal distribution table is  

         Z_{\alpha } =  2.33

   The  null hypothesis is  

           H_o  :  \mu  =  60 \ seconds

   The alternative hypothesis is  

          Ha :  \mu \ne 60 \ seconds      

Generally the sample mean is mathematically represented as

       \= x  =  \frac{\sum x_i }{n  }

where  n = 15

 So  

      \= x  =  \frac{ 68+ 82 +  38 +  62 + 41+ 25 + 57 + 64+67+ 47+ 61+ 71+ 91+ 87+ 64}{15}

      \= x  =  61.67

The standard deviation is mathematically represented as

     \sigma  =\sqrt{  \frac{ \sum  (x_i -  \= x )^2}{n} }

substituting values

      \sigma  =\sqrt{  \frac{ \sum  (68-61.67)^2 + ( 82-61.67 )^2  +   (38 -61.67)^2 +  62-61.67)^2 + (41-61.67)^2 +(25-61.67)^2 +( 57+61.67)^2 }{15} }           \sqrt{  \frac{  ( \cdot  \cdot  + (  64-61.67)^2 + (67-61.67)^2 +(47-61.67)^2 + (61-61.67)^2+  (71-61.67)^2 + (91 -61.67)^2+( 87-61.67)^2 +  (64-61.67)^2}{15} }=>   \sigma  =  18.23

The  test statistics is evaluated as  

      t  =  \frac{\= x  - \mu  }{ \frac{\sigma }{\sqrt{n} } }

substituting values

       t  =  \frac{61.67  -60  }{ \frac{18.23 }{\sqrt{ 15} } }

      t  =  0.354

Now comparing the statistics and the critical value of the level of significance we see that the the test statistics is less than the critical value

Hence the we fail to reject the null hypothesis which mean that these times are from a population with a mean equal to 60 seconds

So we can state that yes the students are reasonably good at estimating one minute given that the sample mean is not far from the population mean

4 0
3 years ago
What is the answer to this problem
Vlad1618 [11]

Answer:

D

Step-by-step explanation:

32-5=27

then you need the the 4p to end up being greater than or equal to 27.

so p would have to be any number about 7.

4 0
4 years ago
If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen
MrRissso [65]

Answer:

Option A

Step-by-step explanation:

Step 1: Naming both equations:

Eq. 1: 3x + 2y=-21\\Eq. 2 : x-3y=4

Step 2: Isolating x in Eq. 2

x=3y+4

Step 3: Replacing x in Eq. 1

3(3y+4)+2y=-21

Therefore, the answer is Option A

4 0
4 years ago
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