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diamong [38]
3 years ago
13

The average final exam score for the statistics course is 77% and the standard deviation is 8%. A professor wants to see if the

average exam score will be higher for students who are given colored pens on the first day of class. The final exam scores for the 17 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal. 75, 78, 74, 89, 76, 92, 81, 87, 77, 79, 75, 81, 52, 80, 98, 72, 78 What can be concluded at the 0.05 level of significance
Mathematics
1 answer:
pochemuha3 years ago
5 0

Answer:

There is not enough evidence to support the claim that average score for those given colored pen is greater than 77

Step-by-step explanation:

Given the data : 75, 78, 74, 89, 76, 92, 81, 87, 77, 79, 75, 81, 52, 80, 98, 72, 78

Using calculator :

Sample mean, xbar = 79.06

Sample standard deviation = 9.85

Sample size, n = 17

H0 : μ = 77

H1 : μ > 77

The test statistic : (xbar - μ) ÷ (s / sqrt(n))

(79.06 - 77) ÷ (9.85 / sqrt(17))

2.06 ÷ (9.85 / sqrt(17))

= 0.8623

The Pvalue from Tscore :

Pvalue = 0.20063

Since pvaue is > α ; we fail to reject the null ` There is not enough evidence to support the claim that average score for those given colored pen is greater than 77

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postnew [5]

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For example, the first question.

y=-3x+2

To find the y-intercept, x = 0

So substitute x = 0 in the equation.

y=0+2\\y=2

[Note]: You don't need to find the y-intercept, because from, y=ax+b

a is slope and b is y-intercept, you know b then you know y-intercept. For example b = 2 then y-intercept is at 2.

To find the x-intercept, y = 0

-3x+2=0\\-3x=-2\\x=\frac{2}{3}

Therefore, y-intercept = 2 and x-intercept = 2/3

(Try do another problems, just do the same. When you want to find the y-intercept, just look at the value of b or substitute x = 0 and When you want to find the x-intercept, just substitute y = 0 then solve for x.)

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Step-by-step explanation:

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Hey there!

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<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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