Answer: -1.1
The answer is: Negative 1 point 1 : -1.1
Lets turn E into x and F into y.
We already know that x is 0.8. And if y/x = 0.6, we have to figure that out.
y/x = 0.6
y/0.8 = 0.6
Multiply by 8 to get y = 0.48.
So we have to find P(xy)
So if we know that x = 0.8 and y = 0.48 then all we have to do is multiply 0.48 and 0.8.
0.48 * 0.8 = 0.384
P(E and F) is 0.384.
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Answer:
53.57%
Step-by-step explanation:
We have to calculate first the specific number of events that interest us, if at least 3 are girls, they mean that 2 are boys, therefore we must find the combinations of 3 girls of 5 and 2 boys of 3, and multiply that, so :
# of ways to succeed = 5C3 * 3C2 = 5! / (3! * (5-3)!) * 3! / (2! * (3-2)!)
= 10 * 3 = 30
That is, there are 30 favorable cases, now we must calculate the total number of options, which would be the combination of 5 people from the group of 8.
# of random groups of 5 = 8C5 = 8! / (5! * (8-5)!) = 56
That is to say, in total there are 56 ways, the probability would be the quotient of these two numbers like this:
P (3 girls and 2 boys) = 30/56 = 0.5357
Which means that the probability is 53.57%
The null hypothesis suggests that the two samples come from the same distribution(s), and the experimental hypothesis suggests that the two samples come from different distribution(s).
