$11,000 will bet the cost in 7 years
Given:
Original cost: $25,000
Depreciation rate: 8%
Term: 7 years
Formula for Depreciation:
A = C ( 1 - ( r ) (t) )
A = Future Value
C = Original Cost
r = rate
t = term
Solution:
Substitute the given values to the formula for depreciation.
A = $25,000( 1 - ( 0.08)(7))
A = $25,000( 1 - .56 )
A = $25,000(0.44 )
A = $11,000
Problem One
Call the radius of the second can = r
Call the height of the second can = h
Then the radius of the first can = 1/3 r
The height of the first can = 3*h
A1 / A2 = (2*pi*(1/3r)*(3h)] / [2*pi * r * h]
Here's what will cancel. The twos on the right will cancel. The 3 and 1/3 will multiply to one. The 2 r's will cancel. The h's will cancel. Finally, the pis will cancel
Result A1 / A2 = 1/1
The labels will be shaped differently, but they will occupy the same area.
Problem Two
It seems like the writer of the problem put some lids on the new solid that were not implied by the question.
If I understand the problem correctly, looking at it from the top you are sweeping out a circle for the lid on top and bottom, plus the center core of the cylinder.
One lid would be pi r^2 = pi w^2 and so 2 of them would be 2 pi w^2
The region between the lids would be 2 pi r h for the surface area which is 2pi w h
Put the 2 regions together and you get
Area = 2 pi w^2 + 2 pi w h
Answer: Upper left corner <<<<< Answer
Answer:
q < 56
Step-by-step explanation:
q +12 -2(q -22) > 0
q +12 -2q +44 > 0
56 -q > 0
q < 56
Answer:
- Question 1a. i)
- Question 1a. ii)
- Question 1b)
Explanation:
<u><em>Question 1 a. i) Find the value of x.</em></u>
For the smalll triangle you can write:
For tthe big triangle:
Substitute:
Solve for x:
<u><em>Question 1a ii) Find the volume of the frustrum</em></u>
- Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m
Formula:
Substitute:
- Find the volume of a cone with heigth = 1.8m and radius = 1m
- Subtract the volume of the small cone from the volume of the big cone
<u><em>Question 1b. Calculate the volume of the bin</em></u>
<u>i) Upper frustrum</u>
This is the same frustrum from the equation of above, thus ist volume is 27.6m³.
<u>ii) Lower frustrum</u>
<u>iii) Add the volume of the two frustrums</u>
Answer:
y = 5
Step-by-step explanation:
cross-multiply:
6y = 30
y = 5
