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aivan3 [116]
3 years ago
8

The triangular prism above has been created with two equilateral triangles and three congruent rectangles the height of the tria

ngle is 3.5 inches find the surface area of the triangular prism
Mathematics
1 answer:
Marrrta [24]3 years ago
5 0

Answer:

108 inches square.

Step-by-step explanation:

Here

base= b= 4 inches

height = h=w=  3.5 inches

and length = l= 9  inches

The surface area is the total area of all the sides of the prism. So the area of the 2 triangles is given by

Area of the 2 Δs= b* h= 4*3.5=  13.5 inches square

Area of the 3 rectangles = l*w(3)= 3( 9*3.5)= 94.5  inches square.

Total area = 13.5 + 94.5 = 108 inches square

This can be found by applying another formula.

Surface area of the triangular prism = bh + ( s1+s2+s3) H

                                                         = 4*3.5 + (9+9+9)3.5

                                                          = 13.5 + 94.5= 108 inches square.

where H is the width of the recatngles which is equal to the height of the triangles.

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7) PG & E have 12 linemen working Tuesdays in Placer County. They work in groups of 8. How many
BabaBlast [244]

Part A

Since order matters, we use the nPr permutation formula

We use n = 12 and r = 8

_{n}P_{r} = \frac{n!}{(n-r)!}\\\\_{12}P_{8} = \frac{12!}{(12-8)!}\\\\_{12}P_{8} = \frac{12!}{4!}\\\\_{12}P_{8} = \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1}\\\\_{12}P_{8} = \frac{479,001,600}{24}\\\\_{12}P_{8} = 19,958,400\\\\

There are a little under 20 million different permutations.

<h3>Answer: 19,958,400</h3>

Side note: your teacher may not want you to type in the commas

============================================================

Part B

In this case, order doesn't matter. We could use the nCr combination formula like so.

_{n}C_{r} = \frac{n!}{r!(n-r)!}\\\\_{12}C_{8} = \frac{12!}{8!(12-8)!}\\\\_{12}C_{8} = \frac{12!}{4!}\\\\_{12}C_{8} = \frac{12*11*10*9*8!}{8!*4!}\\\\_{12}C_{8} = \frac{12*11*10*9}{4!} \ \text{ ... pair of 8! terms cancel}\\\\_{12}C_{8} = \frac{12*11*10*9}{4*3*2*1}\\\\_{12}C_{8} = \frac{11880}{24}\\\\_{12}C_{8} = 495\\\\

We have a much smaller number compared to last time because order isn't important. Consider a group of 3 people {A,B,C} and this group is identical to {C,B,A}. This idea applies to groups of any number.

-----------------

Another way we can compute the answer is to use the result from part A.

Recall that:

nCr = (nPr)/(r!)

If we know the permutation value, we simply divide by r! to get the combination value. In this case, we divide by r! = 8! = 8*7*6*5*4*3*2*1 = 40,320

So,

_{n}C_{r} = \frac{_{n}P_{r}}{r!}\\\\_{12}C_{8} = \frac{_{12}P_{8}}{8!}\\\\_{12}C_{8} = \frac{19,958,400}{40,320}\\\\_{12}C_{8} = 495\\\\

Not only is this shortcut fairly handy, but it's also interesting to see how the concepts of combinations and permutations connect to one another.

-----------------

<h3>Answer: 495</h3>
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