Answer:
divide 10 by two
Step-by-step explanation:
easy
Draw a right angled triangle ABC, where <B = 90 degrees
<span>BC is the base, and BC = 12 m and C represents spot light on the ground and B is foot of the wall </span>
<span>Draw a perpendicular DE from a point D on hypotenuse, AC to a point E on BC </span>
<span>DE represents walking man and DE = 2 m </span>
<span>Now AB represents height of shadow, let AB = y </span>
<span>let EC = x </span>
<span>from similar triangles, ABC and DEC </span>
<span>AB/DE = BC/EC </span>
<span>y/2 = 12/x </span>
<span>y = 24/x </span>
<span>differentiating with respect to t </span>
<span>dy/dt = - (24/x^2) dx/dt </span>
<span>substitute x = (12 - 4) = 8 and dx/dt = 1.9 m/s </span>
<span>dy/dt = - (24 / 64)(1.9) </span>
<span>= -0.7125 </span>
<span>length of shadow is decreasing at the rate of 0.7125 m /s</span>
Answer:
60 feet
Step-by-step explanation:
The height, h (in meters), of the object launched from a platform is represented by the equation
where x is the time (in seconds) passed after the launch.
The time of launch is 
(0 seconds passed after the launch)
Substitute to find the height:
Answer:
y=2x+9
Step-by-step explanation:
Hope this helps ;)
