Find the value of x

Rashaad leans a 16-foot ladder against a wall so that it forms an angle of 66° with the

ehidna [41]

Answer:

is it right right answer

4 0

2 years ago

A 15-ft ladder is propped against a vertical wall and makes a 72 ̊ angle with the ground. How far is the foot of the ladder from

murzikaleks [220]

We first approach this problem by illustrating the situation. Refer to the diagram attached.

From the diagram, we can clearly see that we need to simply solve for the length marked x in order to find the distance between the foot of the ladder to the base of the wall.

Remember SOHCAHTOA. We can apply here the concept of cosine since we have the angle. Incorporationg x into the equation, we can simply make use of the relation cosine 72° = adjacent/hypotenuse.

$cos(72deg)= \frac{x}{15}$
$15cos(72deg)=x$
$x=4.6$

ANSWER: The distance between the foot of the ladder and the base of the wall is 4.6 feet.

6 0

3 years ago

Wanda has $640 in her checking account. She pays her landlord $75 per week for rent.Which function best models the linear relati

umka21 [38]

Answer:

The function best describe the linear relationship be y = 640 - 75x.

Step-by-step explanation:

As given

Wanda has $640 in her checking account.

She pays her landlord $75 per week for rent.

Let us assume that the number of weeks be x.

Let us assume that the y reresented the money in the account after x weeks.

Than the function becomes

y = 640 - 75x

Therefore the function best describe the linear relationship be y = 640 - 75x.

6 0

4 years ago

What is the solution for x in the given equation? The square root of 9x +7 + the square root of 2x = 7

cestrela7 [59]

Answer:

The solution is x =2 for the given equation $\sqrt{9x+7} +\sqrt{2x}=7$

Step-by-step explanation:

We need to find the solution for x in the given equation.

$\sqrt{9x+7} +\sqrt{2x}=7$

Solving:

Subtract $\sqrt{2x}$ from both sides

$\sqrt{9x+7} =7-\sqrt{2x}$

Taking square on both sides

$(\sqrt{9x+7})^2 =(7-\sqrt{2x})^2\\Using\,\, (a-b)^2 = a^2-2ab-b^2\\9x+7=(7)^2-2(7)(\sqrt{2x})+(\sqrt{2x})^2\\9x+7=49-14\sqrt{2x}+2x\\9x-2x+7-49=-14\sqrt{2x}\\7x-42=-14\sqrt{2x}\\Taking\,\,square\,\,on\,\,both\,\,sides\\(7x-42)^2=(-14\sqrt{2x})^2\\49x^2-2(7x)(42)+(42)^2= 196(2x)\\49x^2-588x+1764=392x\\49x^2-588x+1764-392x=0\\49x^2-980x+1764=0\\Using \,\,quadratic \,\, equation \,\,to \,\, find \,\, value \,\, of \,\, x \\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a= 49, \, b= -980 \,\,and\,\, c = 1764$