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valina [46]
3 years ago
15

Anthony, Brian and Chris are hired for a job. If Anthony and Brian are working together they will finish the job in minutes. If

Anthony and Chris are working together they will finish the job in minutes. If Brian and Chris are working together, they will finish the job in hour. If the Chris is working alone, how long will it take him to finish the job
Mathematics
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

12.5

Step-by-step explanation:

Let  individual time taken by Anthony, Brian and Chris = t1 , t2 , t3 respectively

So, total time taken by A & B  = 1 / t1  + 1 / t2 , lets suppose = 10  {i}

Total time taken by A & C = 1 / t1  + 1 / t3 , lets suppose = 15 {ii}

Total time taken by B & C = 1 / t2  + 1 / t3 , lets suppose = 20 {iii}

From {i} , 1 / t2 = 10 - 1 / t1

From {ii} 1 / t1 = 15 - 1 / t3

By above two eqtns ,  1 / t2 = 10 - (15 - 1 / t3)

1 / t2 = 1 / t3 - 5

Putting in {iii} , 1 / t3 - 5 + 1 / t3 = 20

2 / t3 = 25

t3 = 12.5

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sveta [45]

Answer:

\frac{4}{9}

Step-by-step explanation:

Two events are independent of each other, this is called Compound Probability. Classical example is if two coins are filped, what is the probability of getting two heads in a row.?

Answer: each has 50% probability because there are two states only, either H or T. since we have two coins the probability of getting two heads in row is the product of obtaining heads for each individual coin (which is independent of each other). or is \frac{1}{2}×\frac{1}{2} = \frac{1}{4} = 25%. (Notice!).

Back to our problem, now here we have 3 paint brands and one of them is the right paint brand and two of them are not correct brands. so the prabablity that the customer has picked not correct brand is \frac{2}{3} and her husband has not picked correct brand is also \frac{2}{3}, since two probabilities are compound probabilities i.e indepandant of each other the probablity that both woman and her husband fail get correct brand is the product of the two and is = \frac{2}{3}×\frac{2}{3} = \frac{4}{9}.

4 0
3 years ago
Given that △ABC ≅ △DEF , m∠E=3y+20, m∠B= 10 +5y, and m∠A=5y , answer the following:
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Let H represent heads and T represent tails.

Writing HH means we get two heads and HT means we get heads first, then tails second, and so on.

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Of those four outcomes, two of them have exactly one head show up (HT and TH). The probability of getting exactly one head is 2/4 = 1/2, so this is why Jose is correct.

8 0
3 years ago
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