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Lilit [14]
3 years ago
8

HELP I WILL MARK YOU BRAINLIEST PLEASE

Mathematics
1 answer:
valkas [14]3 years ago
8 0

Question: Mai had $14.50. She spent $4.35 at the snack bar and $5.25 at the arcade. What is the exact amount of money Mai has left?

Answer: $4.90

Steps: Step 1: Find operation: The operation in this problem is subtraction because words such as "spent" means that she used money, meaning we subtract.

Step 2: Figure out order of numbers: Now that we know that the operation is subtraction, we need to know what numbers to subtract. The problem says that Mai had $14.50, which means that this is the total amount of money she had when she started. Spent means that Mai used money, so this means that we subtract like this: $14.50-$4.35-$5.25.

Step 3: Subtract: Now that we know what operation to use, and what order to use the numbers, we can finish the problem:

<h2>                   $14.90</h2><h2>            -      $  4.35</h2><h2>           -------------------</h2><h2>                    $10.15</h2><h2>              -    $  5.25</h2><h2>           --------------------</h2><h2>                      $4.90 </h2>

--------------------------------------------------------------------------------------------------------------

Question: Kristina rides her bicycle 384.25 miles over 29 weeks to and from her job. How many miles does she ride each week to and from her job if she rides the same amount each week?

Answer: 13.25

Steps: 1: Find operation: To solve this question, we need to find the operation. Words such as "same amount each week" mean that this is division.

Step 2: Figure out order of numbers: Now, we need to figure out what to divide by. We divide 384.25 by 29 because it say that she rides 384.25 miles over 29 weeks.

Step 3: Divide: Now, we will solve the equation: 384.25 divided by 29 is 13.25, so the answer is 13.25.

Hope this helps you!

P.s. Sorry I could not show how to divide 384.25 by 29.

                                 

<h2>                     </h2>
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A study conducted on 40,000 words in the English language found that about 6,670 words started with the letter T, which is the m
melisa1 [442]

To answer this problem, first let us calculate for the theoretical probability obtained from the study conducted:

Theoretical Probability = 6,670 / 40,000

Theoretical Probability = 0.16675 = 0.17

From the given choices, the list of words which can give this similar amount of probability is:

“to, sarcastic, epithet, for, less, corruptible, than, the, offspring, open, any, primary, loyalty, table, out, whom, example, who, mention, say”

In this set of words, the number of words starting with letter T is 4. Calculating for the probability of getting a word starting with T in this set is:

Sample probability = 4 / 20

<span>Sample probability = 0.20</span>

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3 years ago
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Solve for c.<br><br> 2(c +1) = 10
coldgirl [10]

Answer:

c=4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2(c+1)=10

(2)(c)+(2)(1)=10(Distribute)

2c+2=10

Step 2: Subtract 2 from both sides.

2c+2−2=10−2

2c=8

Step 3: Divide both sides by 2.

2c

2 = 8

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X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y
andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}

Part b.

Consider V(3X + 2Y)

\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

3 X+2 Y \sim N(18,77)

Thus,

P(3 X+2 Y < 18)=0.5

Part d.

Consider P(3X + 2Y < 28)

Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}

\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

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2 years ago
Please help with this
ioda

Answer:

Some have multiple choices. See below for additional comments.

  • a) iii
  • b) i
  • c) v
  • d) ii
  • e) iv

Step-by-step explanation:

i -- slope-intercept form. Shows the slope and the y-intercept

ii -- slope-intercept form. Shows the slope and the x-intercept

iii -- intercept form. Shows both the x- and y-intercepts

iv -- standard form.

v -- point-slope form. Shows the slope and one point on the line.

vi -- another point-slope form. Shows the slope and one point on the line

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With the above forms in mind, ...

a) both intercepts are best shown in form iii

b) the slope is shown in forms i, ii, v, vi. Form i is the most uncluttered.

c) points are shown in forms v and vi. Form v may be least confusing.

d) the sign can be readily determined in form ii.

e) testing the given point is easily done using forms ii and iv. Form iv may be the best for this.

_____

<em>Additional comments</em>

Since each of these forms of the equation has utility in different situations, it can be worthwhile to learn the different forms. For example, I like the standard form for making perpendicular lines, though any of the "slope-" forms can be useful for that, too. The useful form to start with will be the one that best relates to the information given. (For two points given, there is a "2-point form" not shown here.)

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