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3 years ago

Is a dilated segment still a segment ?

Mathematics

1 answer:

OLEGan [10]3 years ago

8 0

Answer:

Still a segment

Step-by-step explanation:

When a segment is dilated by a scale factor of r = 1, then the segment and its image would be the same length. When the points P and Q are on a line containing the center, then the dilated points P' and Q' will also be col linear with the center producing an image of the segment that is a segment.

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the legs of an isosceles right triangle each measure 10 inches what is the length of the hypotenuse of this triangle to the near

k0ka [10]

Use the Pythagorean theorem:
$(\hbox{leg})^2+(\hbox{leg})^2=(\hbox{hypotenuse})^2 \\
10^2+10^2=x^2 \\
100+100=x^2 \\
x^2=200 \\
x=\sqrt{200} \\
x \approx 14.1$

The length of the hypotenuse is approximately 14.1 in.

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3 years ago

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Daniel [21]

Answer:

Step-by-step explanation:

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3 years ago

Hi! I'm 12 years old trying to move up in maths, does anyone have any tips about any one of these topics?

Mars2501 [29]

Answer:

For number remember that the negative number are smaller, but if it question like this which one is bigger -5 or -6 will -5 will be the answer because it is not smaller than -6. For ratios just remember divide or number of something like there are 3 to 8 child in the classroom then thee ratios would be 3:8. Lastly for the times tables learn all of your times tables like your favorite game, so things will be easier on you.

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3 years ago

Two expressions are shown below. Explain whether or not expressions P and Q are equivalent

bulgar [2K]

Answer:

I don't see any expressions shown below.

Step-by-step explanation:

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3 years ago

What is the equation of the line (in slope-intercept form) that passes through the given point and is

Otrada [13]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmmm what's the slope of the equation above anyway?

$\bf x+y=6\implies y = \stackrel{\stackrel{m}{\downarrow }}{-1}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-1\implies \cfrac{-1}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{-1}}\qquad \stackrel{negative~reciprocal}{\cfrac{1}{1}\implies 1}}$

so we're really looking for the equation of a line whose slope is 1 and runs through (-5,-6).

$\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{-6})~\hspace{10em} \stackrel{slope}{m}\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{1}[x-\stackrel{x_1}{(-5)}] \\\\\\ y+6=1(x+5)\implies y+6=x+5\implies y=x-1$

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3 years ago