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3 years ago

KLM is isosceles. Calculate the segment EF from the data in the drawing. HELP!!

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

5 0

Answer:

4.5 cm

Step-by-step explanation:

KL = LM as triangle is isosceles

LM = KM as LF = FM = KN = NM, so the triangle is equilateral

EF ║ NM as LE⊥EF and LN⊥NM

EF is half the midsegment as ∠KLN ≅ ∠MLN, and LN is angle bisector of ∠KLM

Midsegment is half the side length, and all sides are 18 cm.

EF = 1/2(1/2*18) = 4.5 cm

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3 years ago

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Answer:conjectured that F(n)≈0.72∗n∗f(n). Following that clue, we can find the following identity holds for all cases we tested by trial and error.

F(n)=nf(n)−(n−2)f(n−2)+(n−4)f(n−4)−(n−6)f(n−6)+⋯

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Step-by-step explanation:

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3 years ago

-7p-10=-8p-9p<br><br>what is p?

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3 years ago

A number is selected from the set {1, 2, 3, 5, 15, 21, 29, 38, 500}. If equal elemental probabilities are assigned, what is the

Zanzabum

Answer:

The required probability is $\frac{7}{9}$ .

Step-by-step explanation:

Set given is:

S = {1, 2, 3, 5, 15, 21, 29, 38, 500}

Total number of elements in set, $n(S)$ = 9

Let A be the event that the number is less than 29 ({1, 2, 3, 5, 15, 21}).

Number of items in the event A, $n(A)$ = 6

Probability of event A,

$P(A) = \dfrac{n(A)}{n(S)}}=\dfrac{6}{9} \Rightarrow \dfrac{2}{3}$

Formula for probability of any event E:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Let B be the event that the number is odd (either of {1,3,5,15,21,29}).

Number of items in the event B, $n(B)$ = 6

Probability of event B,

$P(B) = \dfrac{n(B)}{n(S)}}=\dfrac{6}{9} \Rightarrow \dfrac{2}{3}$

The event A and B have a few elements in common, i.e. numbers less than 29 which are odd as well.

The common elements are represented as:

$A \cap B = \{1, 3, 5, 15, 21\}$

$n(A\cap B) = 5$

$P(A \cap B ) = \dfrac{n(A \cap B)}{n(s)}\\\Rightarrow P(A \cap B) = \dfrac{5}{9}$

To find probability of selecting a number which is either less than 29 (event A) or odd (event B),

We have to find $P(A\ or \ B)$ which is represented as $P(A \cup B)$ and the formula is:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)\\\Rightarrow \dfrac{2}{3} + \dfrac{2}{3} - \dfrac{5}{9}\\\Rightarrow \dfrac{12-5}{9}\\\Rightarrow \dfrac{7}{9}$

The required probability is $\frac{7}{9}$ .

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3 years ago