Answer:
8,800,000cars
Step-by-step explanation:
Given the initial amount of cars = 80,000,000
If there is 10 % increase in the first year;
Increment = 10% of 80,000,000
Increment = 0.1 * 80,000,000
Increment = 8,000,000
Amount of car in year 2 = 80million + 8million = 88million
Year3;
Amount of car in year 3 = 88,000,000+(10%of88million)
Amount of car in year 3 = 88,000,000+8,800,000
Amount of car in year 3 =96,800,000
Differences in the number of cars = 96,800,000 - 88,000,000
Differences in the number of cars = 8,800,000cars
<em>Hence there are 8,800,000cars in years 3 than year 2</em>
