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AfilCa [17]
4 years ago
6

Please help!

Mathematics
1 answer:
lidiya [134]4 years ago
6 0
Let’s start out by breaking down the equation

1. eight more than. we know this must mean we are adding 8, so (+ 8)

2. the difference of a number and sixteen. we know the number (x) and 16 are being subtracting as indicated by the word difference, so (x-16)

now let’s combine them (x-16) + 8

let’s set it equal to 0, just to confirm it is correct.
(x-16) +8 = 0
x-16 = -8
x = 8

so substituting x for 8 in the translation: (8-16) + 8 = 0
-8 +8=0

it is correct! :)
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Which is bigger 0.07 or 0.005?
VMariaS [17]
0.07 is the larger number out of the two
4 0
4 years ago
Construc t a 95% confidence interval for the population standard deviation σ of a random sample of 15 men who have a mean weight
GrogVix [38]

The 95% confidence interval for the population standard deviation will be,

$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\

simplifying the equation, we get

$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288

The 95% confidence interval exists (9.887, 21.288).

<h3>What is the  95% of confidence interval?</h3>

A random sample of 15 men exists selected. The mean weight exists at $165.2 pounds and the standard deviation exists at $13.5 pounds. The population exists normally distributed.

So, $n=15, \bar{X}=165.2, s=13.5$

where n exists the sample size, $\bar{X}$ exists the sample size

s exists the sample standard deviation.

The degrees of freedom will be n - 1 i.e.15 - 1 = 14.

For a 95% confidence interval, the level of significance will be $\alpha=0.05$.

The 95% confidence interval for the population standard deviation will be,

$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\

substitute the values in the above equation, we get

$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi^{2}} 0.05} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0}^{2}}} \\

$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.975}^{2}}} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.025}^{2}}} \\

simplifying the above equation, we get

$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288

The 95% confidence interval exists (9.887, 21.288).

To learn more about confidence interval refer to:

brainly.com/question/14825274

#SPJ4

6 0
2 years ago
Spaceship Earth, a spherical attraction at Walt Disney World’s Epcot Center, has a diameter of 50 meters. Find the surface area
Black_prince [1.1K]

The surface area of Spaceship Earth is: 7850 m^2

Step-by-step explanation:

Given

Diameter of spherical structure = d = 50 meters

As the attraction is in the form of a sphere, its radius will be used to find the surface area.

Radius = r = \frac{d}{2} = \frac{50}{2} = 25\ m

The formula for surface area of sphere is:

SA = 4\pi  r^2\\= 4 * 3.14 * (25)^2\\= 4*3.14*625\\=7850\ m^2

The surface area of Spaceship Earth is: 7850 m^2

Keywords: surface area, sphere

Learn more about surface area about:

  • brainly.com/question/1859222
  • brainly.com/question/1993757

#LearnwithBrainly

6 0
3 years ago
The weight y of an object on Jupiter is proportional to the weight x of the object on Earth. An object that weighs 150 pounds on
svetoff [14.1K]
Weight of an object=J
x=J/(379.2/150)
x=J/2.528

y=12.64/2.528
y=5

Hope this helps :)
7 0
3 years ago
Read 2 more answers
46 decreased by twice the number
snow_lady [41]

-46

Hope this helps!

May I please have brainliest? :D

4 0
3 years ago
Read 2 more answers
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